A Coolie raises a box of mass 20 kg to a height of 1.5m. If the force of gravity on 1 kg is 10N. The work done by the Coolie is
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Answer: Vertical height of rocket is 824.24ft
Explanation: see attachment.
Opp/ Adj = Tan 70°
h/ 300 = Tan 70°
h= 300tan 70°
h = 824.24ft
Their velocity afterward is v=3.467 m/s
Explanation:
Given:
Mass of the first football player= 91.5 kg
Initial velocity of the football player 3.73 m/s
Mass of second football player=63.56 kg
Initial velocity of the second football player=3.09 m/s
To find:
Final velocity of both players=?
Solution:
According to the law of conservation of momentum,
Initial momentum =final momentum
mathematically represented as
...........................(1)
where
=intial velocity of the football player
= inital velocity of second football player
=finall velocity of the first football player
=final velocity of second football player
after tackling , both the football players moves with the same velocity,
so
Hence equation (1) becomes
now substituting the values,
v=3.467 m/s