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arsen [322]
3 years ago
14

What is the emf of a battery that increases the electric potential energy of 0.060 CC of charge by 0.70 JJ as it moves it from t

he negative to the positive terminal?
Physics
2 answers:
Evgen [1.6K]3 years ago
5 0

Answer:

emf = 11.667 V

Explanation:

Given: charge q = 0.060 C, electric potential energy E =0.70 J,

Solution :

by definition 1 volt = 1 joule per coulomb

so Voltage = emf = E/C

emf =  0.70 J / 0.060 C

emf = 11.667 V

Anastasy [175]3 years ago
5 0

Answer:

11.67 V.

Explanation:

Workdone by a charge, W = q × v

Where,

W = 0.7 J

q = 0.06 C

v = W/q

= 0.7/0.06

= 11.67 V

Emf = 11.67 V

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Beings on spherical asteroid have observed that a large rock is approaching their asteroid in a collision course. At 7514 km fro
luda_lava [24]

Answer:

c. 4.582\times10^{21} kg

Explanation:

r_{i} = Initial distance between asteroid and rock = 7514 km = 7514000 m

r_{f} = Final distance between asteroid and rock = 2823 km = 2823000 m

v_{i} = Initial speed of rock = 136 ms⁻¹

v_{f} = Final speed of rock = 392 ms⁻¹

m = mass of the rock

M = mass of the asteroid

Using conservation of energy

Initial Kinetic energy of rock + Initial gravitational potential energy = Final Kinetic energy of rock + Final gravitational potential energy

(0.5) m v_{i}^{2} - \frac{GMm}{r_{i}} = (0.5) m v_{f}^{2} - \frac{GMm}{r_{f}} \\(0.5) v_{i}^{2} - \frac{GM}{r_{i}} = (0.5) v_{f}^{2} - \frac{GM}{r_{f}} \\(0.5) (136)^{2} - \frac{(6.67\times10^{-11}) M}{(7514000)} = (0.5) (392)^{2} - \frac{(6.67\times10^{-11}) M}{(2823000)} \\M = 4.582\times10^{21} kg

8 0
4 years ago
The motion of an object undergoing constant acceleration can be modeled by the kinematic equations. One such equation is xf=xi+v
Arturiano [62]

Answer:

a = 1.72 m/s²

Explanation:

The given kinematic equation is the 2nd equation of motion. The equation is as follows:

xf = xi + (Vi)(t) + (1/2)(a)t²

where,

xf = the final position =  5000 m

xi = the initial position = 1000 m

Vi = the initial velocity = 15 m/s

t = the time taken = 60 s

a = acceleration = ?

Therefore,

5000 m = 1000 m + (15 m/s)(60 s) + (1/2)(a)(60 s)²

5000 m = 1000 m + 900 m + a(1800 s²)

5000 m = 1900 m + a(1800 s²)

5000 m - 1900 m = a(1800 s²)

a(1800 s²) = 3100 m

a = 3100 m/1800 s²

<u>a = 1.72 m/s²</u>

5 0
3 years ago
An equinox occurs when
schepotkina [342]
A! Good luck on your test!
6 0
3 years ago
Read 2 more answers
Three equal 1.55-μC point charges are placed at the corners of an equilateral triangle whose sides are 0.500 m long. What is the
kati45 [8]

Answer:

0.12959085 J

Explanation:

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

q = Charge = 1.55 μC

d = Distance between charge = 0.5 m

Electric potential energy is given by

U=k\dfrac{q^2}{d}

In this system with three charges which are equidistant from each other

U=k\dfrac{q^2}{d}+k\dfrac{q^2}{d}+k\dfrac{q^2}{d}

\\\Rightarrow U=k\dfrac{3q^2}{d}\\\Rightarrow U=8.99\times 10^9\times \dfrac{3\times (1.55\times 10^{-6})^2}{0.5}\\\Rightarrow U=0.12959085\ J

The potential energy of the system is 0.12959085 J

6 0
3 years ago
If the mass of an object is doubled, its gravitational force will:
tankabanditka [31]
Increase because the mass of an object aligns with its weight
5 0
4 years ago
Read 2 more answers
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