Answer:

Explanation:
Given that,
The current in the loop, I = 2 A
The radius of the loop, r = 0.4 m
We need to find the magnetic field at a distance 0.09 m along the axis and above the center of the loop. The formula for the magnetic field at some distance is given as follows :

Put all the values,

So, the required magnetic field is equal to
.
<h3><em>If two objects with the same charge are brought towards each other the force produced will be repulsive, it will push them apart. If two objects with opposite charges are brought towards each other the force will be attractive, it will pull them towards each other.</em></h3><h3><em>hope it helps.... thank you....</em></h3>
Answer:
1.44%
Explanation:
The potential energy of a spring is given by

The kinetic energy is

Now x = 12 A
Applying in the first equation

The percentage would be 14400%
at
(makes more sense)

The percentage is 25 % of the kinetic energy
Answer:
2 /s north
Explanation:
Given that,
Velocity due North is 8 m/s and due south is 6 m/s
We need to find the magnitude and the direction of the resulting velocity.
Let North is positive and South is negative. When two velocities are in opposite direction, they adds up. So,

It is positive. So, it is in North direction.
Answer:
1.475×10²⁴ W
Explanation:
I = Solar constant of the sun = 1362 W/m² (measured using satellites with value 1.3608 ± 0.0005 kW/m² the error is due to fact that solar output is not always constant)
r = Radius of earth = 6371 km = 6371000 m (mean radius)
A = Area of earth = (4/3)×π×r³
=(4/3)×π×6371000³ = 1.083×10²¹ m²
P = I×A
⇒P = 1362×1.083×10²¹
⇒P = 1.475×10²⁴ W
∴ Rate at which the whole Earth receives energy from the Sun is 1.475×10²⁴ W