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natta225 [31]
4 years ago
11

The process that occurs when physical forces break rock into smaller pieces without changing the rock's chemical composition is

called ____.
Physics
2 answers:
jek_recluse [69]4 years ago
6 0
<span>Mechanical Weathering</span>
BartSMP [9]4 years ago
4 0
The correct answer is physical weathering, also known as mechanical weathering. An example of this would be when water falls into the cracks of a rock. It freezes during cold times and expands in size, which causes the rock to crack even more. When it melts, the crack is bigger and new water goes inside and cracks it even more, and so on and so forth.
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En una librería un libro de 0.6 kg colocado inicialmente en un estante a 40 cm del suelo fue movido a otro estante con una altur
jeyben [28]

Considerando la definición de energía potencial:

  • la energía potencial del libro inicialmente es 2,3544 J y luego de ser movido a otro estante es 7,6518 J.
  • el cambio en la energía potencial del libro es 5,2974 J.
<h3 /><h3>Definición de energía potencial</h3>

La energía potencial es la energía que mide la capacidad que tiene un sistema para realizar un trabajo en función de su posición. En otras palabras, esta es la energía que tiene un cuerpo situado a una determinada altura sobre el suelo.

La energía potencial gravitatoria es la energía asociada con la fuerza gravitatoria. Esta dependerá de la altura relativa de un objeto a algún punto de referencia, la masa, y la fuerza de la gravedad.

Entonces para un objeto con masa m, en la altura h, la expresión aplicada a la energía gravitacional del objeto es:

Ep= m×g×h

Donde

  • Ep es la energía potencial en julios (J).
  • m es la masa en kilogramos (kg).
  • h es la altura en metros (m).
  • g es la aceleración de caída en m/s² (aproximadamente 9,81 m/s²).

<h3>Energía potencial en cada lugar</h3>

En primer lugar, se sabe inicialmente del libro:

  • m= 0,6 kg
  • g= 9,81 m/s²
  • h= 40 cm= 0,4 m (siendo 1 cm= 0,01 m)

Entonces, reemplazando en la definición de energía potencial:

Ep1= 0,6 kg× 9,81 m/s²× 0,4 m

Resolviendo:

<u><em>Ep1= 2,3544 J</em></u>

Por otro lado, se sabe los siguientes datos del libro luego de ser movido:

  • m= 0,6 kg
  • g= 9,81 m/s²
  • h= 1,30 m

Entonces, reemplazando en la definición de energía potencial:

Ep2= 0,6 kg× 9,81 m/s²× 1,30 m

Resolviendo:

<u><em>Ep2= 7,6518 J</em></u>

En resumen, la energía potencial del libro inicialmente es 2,3544 J y luego de ser movido a otro estante es 7,6518 J.

<h3>Cambio de energía potencial</h3>

El cambio en la energía potencial del libro será la diferencia entre la energía potencial luego de ser movido y la energía potencial inicial del libro:

ΔEp= Ep2 - Ep1

ΔEp= 7,6518 J - 2,3544 J

<u><em>ΔEp= 5,2974 J</em></u>

Finalmente, el cambio en la energía potencial del libro es 5,2974 J.

Aprende más sobre energía potencial:

brainly.com/question/21370800

brainly.com/question/25163940

brainly.com/question/25960490

3 0
2 years ago
HELP ASAP PLZZZZZZ
malfutka [58]
B because the electrons are moving to create a new form. Chemical energy is changing the form.


Hope this helps.
5 0
4 years ago
Identify the 4 components of an atom and what the charge is on each one ?<br><br> Please help
luda_lava [24]

Answer:

Structure Of The Atom: Our current model of the atom can be broken down into three constituents parts – protons, neutron, and electrons. Each of these parts has an associated charge, with protons carrying a positive charge, electrons having a negative charge, and neutrons possessing no net charge.

6 0
3 years ago
Read 2 more answers
What force is required to accelerate to 10 kg object to 5.9 m/s/s?
g100num [7]

Force required to accelerate 10 kg object to 5.9 m/s/s ?

Mass = 10 kg

Acceleration = 5.9 m/s^2

Force = Mass * Acceleration

Force = 10 kg * 5.9 m/s^2

Force = 59 kg m /s^2 = 59 N

3 0
3 years ago
By what factor does the sound intensity increase if the sound intensity level increases from 60 db to 61 db?
tiny-mole [99]

Answer:

\frac{I_{2}}{I_{1}} = 10^{0.1}

Explanation:

The sound intensity level β can be mathematically defined as

\beta(dB) = 10log_{10}(\frac{I}{I_{o} } )

where I_{o} is the reference intensity and is equal to 10^{-12} W/m^{2}.

Now,

\beta_{2} - \beta_{1} = 10 log\frac{I_{2} }{I_{o}} -  10 log\frac{I_{1} }{I_{o}}\\62-60= 10log(\frac{\frac{I_{2} }{I_{o} } }{\frac{I_{1} }{I_{o} } } )\\1=10log(\frac{I_{2} }{I_{1} } )\\\\\frac{I_{2} }{I_{1} }=10^{0.1}

6 0
4 years ago
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