Mass m = 68 kg
center of gravity from his palms x = 0.7 m
center of gravity from his feet x ' = 1 m
forces exerted by the floor on his palms and feet are F and F ' respectively.
with respect to palms :---------------------
( F*0 ) - (W * x ) + [ F ' * (x+x') ] = 0
-mg*0.7 + F ' * 1.7 = 0 where W = weight = mg
F ' * 1.7 = mg * 0.7
F ' = mg * 0.7 / 1.7
= 68 *9.8 * ( 0.7 / 1.7 )
= 274.4 N
with respect to feet :--------------------
( F ' * 0 ) -( W* x ' ) + [F * ( x + x') ] = 0
-mg*1 + [ F * 1.7 ]= 0
F = mg / 1.7
= 392 N
Answer: The displacement is 1 block.
Explanation:
Let's define:
The right is the positive side.
The left is the negative side.
Then if you start at position A, and you walk N blocks to the right, the new position is:
A + N
And if you start at position A, and you walk M blocks to the left, the new position is:
A - M.
In this case, we know that Kayla starts at -3 and she walks 5 blocks to the right.
Then her new position is:
-3 + 5 = 2
Now she walks 3 blocks to the left, then her new position is:
2 - 3 = -1
The displacement will be equal to the difference between the final position (-1) and the initial position (-2)
Then the displacement is:
D = -1 - (-2) = -1 +2 = 1
The displacement is 1 block.
Momentum = mv
= .15 *20
= 3 kgm/s^2
Meiosis is the correct answer because of the fact all the other answers are no where near correct
<span>❅☃ Lever
A winding mountain road is a example of a lever.</span>
