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3 years ago

A winding mountain road is an example of a(n) ____.

Physics

1 answer:

Paul [167]3 years ago

6 0

<span>❅☃ Lever
A winding mountain road is a example of a lever.</span>

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Two electrons are at rest and separated by a distance of 4.32 × 10-10 m. When they are released they accelerate away from each o

sasho [114]

Answer:

Speed of electron when their separation increased by a factor of 4.10 is 9.41 x 10⁵ m/s .

Explanation:

The electric potential energy is given by the relation :

$U = \frac{kq_{1}q_{2} }{r}$

Here q₁ and q₂ are the two charge particles and r is the distance between them and k is electric constant.

In this case, there are two electrons which are separated by the distance 4.32 x 10⁻¹⁰ m.

Let e be the electron charge and r₁ be the distance between them. Then, the initial electric potential energy is :

$U_{1} = \frac{ke^{2} }{r_{1} }$

Now, the distance between the electrons increases by the factor of 4.10. Let r₂ be the new distance between them i.e. r₂ = 4.10 r₁.

Thus, the new electric potential energy is :

$U_{2} = \frac{ke^{2} }{r_{2} }=\frac{ke^{2} }{4.10r_{1} }$

Applying law of conservation of energy :

ΔU = ΔK

Here ΔU is change in electric potential energy and ΔK is change in kinetic energy.

( U₁ - U₂ ) = ( K₂ - K₁ )

Here K₂ and K₁ are initial and final kinetic energy of electron.

Since, the electron initially is at rest, so its initial kinetic energy is zero. Thus, the above equation becomes:

K₂ = U₁ - U₂

$\frac{1}{2}mv^{2}=\frac{ke^{2} }{r_{1} }- \frac{ke^{2} }{4.10r_{1} }$

Here m and v are the mass and final speed of electron respectively.

$v^{2}=\frac{2}{m} \frac{ke^{2} }{r_{1} }(1- \frac{1 }{4.10 })$

Substitute 9.1 x 10⁻³¹ kg for m, 9 x 10⁹ N m² C⁻² for k, 1.6 x 10⁻¹⁹ C for e and 4.32 x 10⁻¹⁰ m for r₁ in the above equation.

$v^{2}=\frac{2}{9.1\times10^{-31} } \frac{9\times10^{9}\times(1.6\times10^{-19})^{2} }{4.32\times10^{-10} }(1- \frac{1 }{4.10 })$

$v^{2}=8.86\times10^{11}$

v = 9.41 x 10⁵ m/s

5 0

3 years ago

With the aid of a string, a gyroscope is accelerated from rest to 32 rad/s in 0.40 s. What is its angular acceleration in rad/s2

Irina-Kira [14]

<h2>Angular acceleration is 80 rad/s² </h2><h2>Number of revolutions undergone is 1.02</h2>

Explanation:

We have equation of motion v = u + at

Initial angular velocity, u = 0 rad/s

Final angular velocity, v = 32 rad/s

Time, t = 0.40 s

Substituting

v = u + at

32 = 0 + a x 0.40

a = 80 rad/s²

Angular acceleration is 80 rad/s²

We have equation of motion s = ut + 0.5 at²

Initial angular velocity, u = 0 rad/s

Angular acceleration, a = 80 rad/s²

Time, t = 0.4 s

Substituting

s = ut + 0.5 at²

s = 0 x 0.4 + 0.5 x 80 x 0.4²

s = 6.4 rad

Angular displacement = 6.4 rad

$\texttt{Number of revolutions = }\frac{6.4}{2\pi}=1.02$

Number of revolutions undergone is 1.02

3 0

3 years ago

You will now use Graphical Analysis to calculate the slope of the line. Choose Analyze from the menu. Select Automatic Curve Fit

Vlad1618 [11]

The value for the slope is <span>M=1.13</span>

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3 years ago

Difference between rest and motion?

Yuki888 [10]

Answer:

Rest and motion are relative terms. In simple terms, an object that changes its position is said to be in motion while the opposite action causes an object to be at rest.

Explanation:

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3 years ago

In what state must matter exist for fusion reactions to take place?<br><br> ...?

valina [46]

It must exist in p<span>lasma state.</span>

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3 years ago

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