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3 years ago

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PLEASE HELP... one early morning Revell went to her car to go to school. she noticed that her entire car was covered w a thin la

yer of yellow green pollen. each pollen grain was created by what type of cell division?
meiosis
mitosis
budding
nuclear fission

1 answer:

Romashka-Z-Leto [24]3 years ago

4 0

Meiosis is the correct answer because of the fact all the other answers are no where near correct

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a student standing between two walls shouts once.he hears the first echo after 3 seconds and the next after 5 seconds. calculate

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Explanation:

It took $t_1 =1.5\:\text{s}$ for the sound to reach the 1st wall and at the same time time, the same sound took $t_2 = 2.5\:\text{s}$ to reach the 2nd wall. Assuming that the sound travels at 343 m/s, then let $x_1$ be the distance of the person to the 1st wall and $x_2$ be the distance to the 2nd wall. So the distance between the walls X is

$X = x_1 + x_2 = v_st_1 + v_st_2 = v_s(t_1 + t_2)$

$\:\:\:\:\:= (343\:\text{m/s})(4.0\:\text{s}) = 1372\:\text{m}$

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3 years ago

The area of the maxila where the teeth attach is called the ??

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Explanation: wiki

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3 years ago

A 200 kg weather rocket is loaded with 100 kg of fuel and fired straight up. It accelerates upward at 30 m/s2 for 35 s , then ru

Gre4nikov [31]

Answer:

a) $h_m=74625\ m$

b) $t=265.55\ s$

Explanation:

Given:

mass of rocket, $m_r=200\ kg$

mass of fuel, $m_f=100\ kg$

acceleration of the rocket consuming fuel, $a=30\ m.s^{-2}$

time after which the fuel exhaust, $t_f=35\ s$

<u>During the phase of fuel exhaustion:</u>

<u>velocity attained by the rocket just as the fuel ends:</u>

$v_f=u+a.t_f$

where:

$u=$ initial velocity of the rocket = 0

$v_f=0+30\times 35$

$v_f=1050\ m.s^{-1}$ this will be the initial velocity for the phase of ascending of the rocket's height under the influence of gravity.

<u>height at which the fuel finishes:</u>

$v_f^2=u^2+2a.h_f$

$1050^2=0^2+2\times 30\times h_f$

$h_f=18375\ m$

<u>During the phase of ascend in height of rocket after the fuel is over:</u>

<u>Time taken to reach the top height after the fuel is over:</u>

$v=v_f+g.t'$

at top v = (final velocity during this course of motion )= 0 $m.s^{-1}$

$0=1050-9.8\times t'$

$t'=107.1429\ s$

<u>Height ascended by the rocket after the fuel is over:</u>

$v^2=v_f^2+2g.h'$

at the top height the velocity is zero

$0^2=1050^2-2\times 9.8\times h'$ (-ve sign denotes that the direction of motion is opposite to that of acceleration)

$h'=56250\ m$

<u>Therefore the maximum altitude attained by the rocket:</u>

$h_m=h_f+h'$

$h_m=18375+56250$

$h_m=74625\ m$

b)

time taken by the rocket to fall back to the earth:

$h_m=v.t_m+\frac{1}{2} g.t_m^2$

where:

$v=$ initial velocity of the rocket during the course of free fall from the top height.

$74625=0+4.9\times t_m^2$

$t_m=123.41\ s$

Now the total time for which the rocket is in the air:

$t=t_f+t'+t_m$

$t=35+107.1429+123.41$

$t=265.55\ s$

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