3Mg + N₂= Mg₃N₂
n(Mg)=12,2g÷<span>24,4g/mol=0,5mol-limiting reagent
</span>n(N₂)=5,16g÷28g/mol=0,18mol
n(Mg₃N₂):n(Mg)=1:3, n(Mg₃N₂)=0,166mol, m(Mg₃N₂)=0,166·101,2=16,8g.
%(N)= 2·Ar(N)÷Mr(Mg₃N₂) = 2·14÷101,2=27,66%=0,2766
%(Mg) = 3·Ar(Mg)÷Mr(Mg₃N₂)= 3·24,4÷101,2=72,34% or 100% - 27,66%= 72,34%.
The answer is 1.56L. Avogadro's Law states that the volume of a gas is directly proportional to the number of moles (or a number of particles) of gas when the temperature and pressure are held constant.
V∝n
V₁/n₁m= V₂/n₂
V₁ = initial volume of gas = 12.5 L
V₂ = final volume of gas = ?
n₁ = initial moles of gas = 0.016 mole
n₂ = final moles of gas = 0.016-0.007 = 0.002 mole
V₁/n₁m= V₂/n₂
V₂= 1.56L
Avogadro's Law is in evidence whenever you blow up a balloon. The volume of the balloon increases as you add moles of gas to the balloon by blowing it up.
Learn more about Volume here:
brainly.com/question/5018408
#SPJ4
Phương trình hóa học: 2Mg+O2->2Mgo
The compound name for H3S5 is hydrosulfide sulfanide sulfide
