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3 years ago

A trunk rotation is a common dyamic flexibility assessment ture or false

1 answer:

6 0

True. It would be false if the statement was "trunk rotation is the most common <em>static</em> flexibility assessment."

So, you're answer should be "true". Hope that helped!

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A 2kg object is tied to the end of a cord and whirled in a horizontal circle of radius 2 m. If the body makes three complete rev

Travka [436]

Answer:

a) 37.70 m/s

b)710.6 m/s²

Explanation:

Given that ;

Mass of object = 2 kg

Radius of the motion = 2m

Frequency of motion = 3 rev/s

The formula to apply is;

v= 2πrf where v is linear speed

v = 2×π×2×3 =12π = 37.70 m/s

Centripetal acceleration is given as;

a= 4×π²×r×f²

a= 4×π²×2×3²

a=710.6 m/s²

5 0

2 years ago

The equation T^2=A^3 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A

kobusy [5.1K]

Answer:

D. 2^(3/2)

Explanation:

Given that

T² = A³

Let the mean distance between the sun and planet Y be x

Therefore,

T(Y)² = x³

T(Y) = x^(3/2)

Let the mean distance between the sun and planet X be x/2

Therefore,

T(Y)² = (x/2)³

T(Y) = (x/2)^(3/2)

The factor of increase from planet X to planet Y is:

T(Y) / T(X) = x^(3/2) / (x/2)^(3/2)

T(Y) / T(X) = (2)^(3/2)

3 0

3 years ago

How are hot spots used to track plate motion

wel

Hot spots are fixed locations in the earth's mantle where heat from the earth's interior rises to the surface and produces volcanism. the earth's plates, which are slowly but constantly moving, are pierced by the uprising magma. as they move away form the hotspot, the volcanoes become dormant and are replaces by new volcanoes. The direction of the line formed from the previous volcanoes indicates the direction :)))

7 0

2 years ago

Read 2 more answers

An AC generator has 80 rectangular loops on its armature. Each loop is 12 cm long and 8 cm wide. The armature rotates at 1200 rp

Sauron [17]

Answer: 28.96 V

Explanation:

Given

No of loops on the armature, N = 80

Length of the loop, l = 12 cm = 0.12 m

Width of the loop, b = 8 cm = 0.08 m

Speed of the armature, 1200 rpm

Magnetic field of the loop, B = 0.30 T

To solve this, we use the formula

V(max) = NBAω

Where,

A = area of loop

A = l*b = 0.12 * 0.08

A = 0.0096 m²

ω = 1200 rpm = 1200 * 2π/60 rad/s

ω = (1200 * 2 * 3.142) / 60

ω = 7540.8 / 60

ω = 125.68 rad/s

Substituting the values into the formula

V(max) = NBAω

V(max) = 80 * 0.30 * 0.0096 * 125.68

V(max) = 80 * 0.362

V(max) = 28.96 V

Therefore, the maximum output voltage of the generator would be 28.96 V

5 0

2 years ago

A laser emits light at power 6.20 mW and wavelength 633 nm. The laser beam is focused (narrowed) until its diameter matches the

Ipatiy [6.2K]

Answer:

a) S = 1.69 10⁹ W/m², b) P = 5.63 Pa , c) F = 20.6 10⁻¹² N

Explanation:

a) The intensity defined as the energy per unit area

S = U / A

Area of a circle is

W = 6.2 mw = 6.2 10-3 W

R = 1080 nm = 1080 10⁻⁹ m = 1.080 10⁻⁶ m

A = π R2

A = π (1,080 10⁻⁶)²

A = 3.66 10 -12 m²

S = 6.2 10-3 / 3.66 10-12

S = 1.69 10⁹ W / m²

b) The radiation pressure

P = 1 / c (dU / dt) / A

S = (dU / dt) / A

P = S / c

P = 1.69 10 9 / 3. 108

P = 5.63 Pa

c) the definition of pressure is force over area

P = F / A

F = P A

F = 5.63 3.66 10⁻¹²

F = 20.6 10⁻¹² N

d) for this we use Newton's second law

F = ma

a = F / m

8 0

3 years ago