a series circuit contains two devices one with a resistance of 10 ohms and one with a resistance of 4 ohms the generator supplie

Question

2 years ago

10

s a voltage of 42 volt what is the magnitude of the current

2 answers:

Bess [88] · Answer 1 · 2022-09-19T11:15:48+03:00

<h2>current flowing through the given circuit is 3 A</h2>

Explanation:

When the resistances are connected in series , the total resistance is the sum of individual resistances .

Thus R = R₁ + R₂

here R₁ is resistance of 10 ohms

and R₂ is resistance of 4 ohms .

Thus total resistance R = 10 + 4 = 14 ohm .

The potential difference applied = 42 volt

Thus current I = $\frac{Potential}{Resistance}$ = $\frac{42}{14}$ = 3 A

Thus current through the circuit is 3 Ampere

Gre4nikov [31] · Answer 2 · 2022-09-19T13:02:22+03:00

6 0

Answer:3A

Explanation: