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Ulleksa [173]
2 years ago
10

a series circuit contains two devices one with a resistance of 10 ohms and one with a resistance of 4 ohms the generator supplie

s a voltage of 42 volt what is the magnitude of the current​
Physics
2 answers:
Bess [88]2 years ago
6 0
<h2>current flowing through the given circuit is 3 A</h2>

Explanation:

When the resistances are connected in series , the total resistance is the sum of individual resistances .

Thus R = R₁ + R₂

here R₁ is resistance of 10 ohms

and R₂ is resistance of 4 ohms .

Thus total resistance R = 10 + 4 = 14 ohm .

The potential difference applied = 42 volt

Thus current I = \frac{Potential}{Resistance} = \frac{42}{14} =  3 A

Thus current through the circuit is 3 Ampere

Gre4nikov [31]2 years ago
6 0

Answer:3A

Explanation:

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Q: The small piston of a hydraulic lift has a cross-sectional of 3.00 cm2 and its large piston has a cross-sectional area of 200 cm2. What downward force of magnitude must be applied to the small piston for the lift to raise a load whose weight is Fg = 15.0 kN?

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Explanation:

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