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musickatia [10]
3 years ago
13

12 and 13 please ◀️⬆️⬇️↗️↩️⬅️↖️↔️

Physics
1 answer:
Black_prince [1.1K]3 years ago
8 0
For 12 density often has unit of grams per cubic centimeter (g/cm3)
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You decide to travel by car for your holiday visits this year. You leave early in the morning to avoid congestion on the roads.
Bond [772]

Answer:

d_t=266.918\ miles is the total distance of the trip travelled.

s_{avg}=54.7895\ mph is the average speed of the journey

Explanation:

Given:

  • duration of first interval, t_1=3.22\ hr
  • speed during the first interval, v_1=65.9\ mph
  • duration of stoppage, t_0=42.1\ min=0.7017\ hr
  • duration of second interval, t_2=0.95\ hr
  • speed during second interval, v_2=57.6\ mph

<u>Now the total distance travelled:</u>

\rm distance=speed\times time

d_t=v_2.t_2+v_1.t_1

d_t=57.6\times 0.95+65.9\times 3.22

d_t=266.918\ miles

<u>The average speed:</u>

\rm speed_{avg}=\frac{total\ distance}{total\ time\ taken}

s_{avg}=\frac{d_t}{(t_0+t_1+t_2)}

s_{avg}=\frac{266.918}{(0.7017+3.22+0.95)}

s_{avg}=54.7895\ mph

4 0
4 years ago
A net force acting on a 5.0 kg box produces an acceleration of 4.2 m/s2. What acceleration, to the nearest tenth of a m/s2, will
SCORPION-xisa [38]

The acceleration that the net force will cause is 7.5 m/s²

To solve this problem, first, we need to find the net force.

⇒ Equation:

F = ma................ Equation 1

⇒ Where:

  • m = mass of the box
  • a = acceleration of the box

From the question,

⇒ Given;

  • m = 5.0 kg
  • a = 4.2 m/s²

⇒ Substitute these values into equation 1

  • F = 5×4.2
  • F = 21 N

We also use the same equation 1 to find the acceleration that the net force will cause to a box of mass 2.8 kg.

⇒ make a the subject in equation 1

  • a = F/m................. Equation 2

⇒ Substitute the appropriate values into equation 2

  • a = 21/2.8
  • a = 7.5 m/s²

Hence, The acceleration that the net force will cause is 7.5 m/s²

Learn more about acceleration here: brainly.com/question/605631

4 0
3 years ago
TRUE OR FALSE. When non-conservative forces are present, the amount of work done increases with the length of the path.
Ymorist [56]

Answer:

True

Explanation:

When non-conservative forces are present, the amount of work done increases with the length of the path, this is true because, when a force is applied, the force does when and the non-conservative forces also do work. Since the non-conservative force work against the force  applied, this tend to increase the net work done by the applied force to compensate for the loss in energy due to the work done by the non-conservative forces.

6 0
3 years ago
If a jet is travelling horizontally at 100m/s at a height of 500m above the ground and a jet drops a bomb to the ground. Where d
Westkost [7]

The bomb strike the ground relative to the point at 1km . B

<h3>How to determine the distance</h3>

Using the equation

h = 1/2 gt^2

500 = 1/2 * 10* t^2

500 = 5t^2

t = √500/5

t = √100

t = 10seconds

To find the distance,

Distance = velocity * time

Distance = 100 ÷ 10

Distance = 1000m = 1km

Therefore, the bomb strike the ground relative to the point at 1km . B

Learn more about projectile distance here:

brainly.com/question/15502195

#SPJ1

8 0
2 years ago
A ball of mass 0.075 kg is fired horizontally into a ballistic pendulum. The pendulum mass is 0.350 kg. The ball is caught in th
Tatiana [17]
1) In the initial situation, the total mechanical energy of the system is given only by the kinetic energy of the ball that is moving with speed v:
E_i =K= \frac{1}{2}m_b v^2
where m_b = 0.075 kg is the mass of the ball.

In the final situation, where the system (ball+pendulum) rises a vertical distance of h=0.145 m, the system is stationary (v=0) so the total mechanical energy of the system is the gravitational potential energy:
E_f = U = (m_b+m_p)gh
where m_p = 0.350 kg is the mass of the pendulum.

For the law of conservation of energy, E_i=E_f , so we can find the initial speed v of the ball:
\frac{1}{2}m_bv^2 = (m_b+m_p)gh
v= \sqrt{ 2 \frac{m_b+m_p}{m_b}gh } =4.0 m/s

2) The kinetic energy lost in the collision is the initial kinetic energy of the ball:
K= \frac{1}{2}m_bv^2= \frac{1}{2}(0.075 kg)(4.0 m/s)^2=0.6 J
8 0
3 years ago
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