Question

Suppose your weekly local lottery has a winning chance of 1/106. You buy lottery from them for x weeks in a row. What is the probability that you never win?

Answer 1

Answer:

The probability mass function  that you never win $^xC_o$ = $(\dfrac{999999}{1000000})^x$

Step-by-step explanation:

Given that;

the winning chance of a weekly local lottery = $\dfrac{1}{10^6}$

= $\dfrac{1}{1000000}$

The probability of losing = 1 - probability of winning (winning chance)

The probability of losing = $1- \dfrac{1}{1000000}$

The probability of losing =$\dfrac{999999}{1000000}$

The probability mass function  that you never win $^xC_o$ = $(\dfrac{1}{10^6} )^0 ( \dfrac{999999}{1000000})^x$

The probability mass function  that you never win $^xC_o$ = $(\dfrac{999999}{1000000})^x$