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svlad2 [7]
3 years ago
7

How many molecules of sodium oxide will be created if 275 grams of sodium reacts with excess oxygen?

Chemistry
1 answer:
DaniilM [7]3 years ago
6 0

Answer:

  • <em>1.34 × 10²⁴ molecules</em>

Explanation:

To calculate the <em>number of molecules of sodium oxide that will be created if 275 grams of sodium reacts with excess oxygen</em>, use the chemical equation to calculate the number of moles and then multiply by Avogadro's number.

<u>1) Balanced chemical equation (given):</u>

  • 4Na + O₂ → 2Na₂O

<u>2) Mole ratio:</u>

  • 4 mol Na : 2 mol Na₂O

<u>3) Calculate the number of moles in 275 g  of Na:</u>

  • n = mass in grams / molar mass
  • mass of Na = 275 g
  • molar mass of Na₂O = 61.9789 g/mol

  • n = 275 g / 61.9789 g/mol = 4.437 mol of Na

<u>4) Set a proportion to find the number of moles of product (Na₂O):</u>

  • 2 mol Na₂O / 4 mol Na = x / 4.437 mol Na

  • x = 4.437 /  2 mol Na₂O = 2.2185 mol Na₂O

<u>5) Convert the number of moles to number of molecules:</u>

  • # molecules = n × 6.022 × 10²³ molecules/mol = 2.2185 mol × 6.022 × 10²³ molecules/mol = 1.34 × 10²⁴ molecules (rounded to 3 significant figures).
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HgC2H6
Fittoniya [83]

Answer:

The number of molecules= 1.33 × 10∧22 molecules

percentage of mercury = 87%

Explanation:

Given data:

mass of dimethyl mercury = 5.10 g

number molecules of dimethyl mercury in 5.10 g = ?

percentage of mercury = ?

Solution:

First of all we will calculate the molar mass of dimethyl mercury.

molar mass of HgC2H6 = 1×200.6 + 2×12 + 6×1 = 230.6 g/mol

we know that,

230.6 g of HgC2H6 = 1 mol = 6.02 × 10∧23 molecules.

so

For the 5.10 g of sample:

5.10 g/230 g/mol = 0.022 moles of HgC2H6

now we will multiply these number of moles with Avogadro number to get number of molecules in 5.10 g of sample.

0.022 × 6.02 × 10∧23 molecules = 0.133  × 10∧23 molecules or

1.33 × 10∧22 molecules.

Percentage of mercury:

Formula:

percentage = (atomic number of Hg × total number of atoms of Hg/ molar mass of HgC2H6) × 100

% age of Hg = (200.6 g/mol× 1/ 230.6 g/mol) × 100

%age of Hg = 0.869 × 100

%age of Hg = 86.99 % or 87 %

6 0
2 years ago
Based on your knowledge of oxygen ion and that Iron can exist as a +2 or a +3 ion. In the formula FeO, what is the charge of the
DerKrebs [107]

Answer:

+2

Explanation:

Oxygen ions always have the charge of -2. Since Fe is in the transition metal stage, it doesn't have a specific set of ions unless specifically shown. In the equation FeO, we would have to have a +2 charge when equalling the two atoms together. So when combines the charges would look like:

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6 0
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In nickel-78, there are 28 protons, 28 electrons, and 50 neutrons.

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8 0
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