Reaction of an alkene with H2 to form an alkane is an example of <u>reduction</u> reaction because there is an <u>increase</u> in the number of C-H bonds.
V1/T1 = V2 / T2
V1 = 3/4(1700) = 1275
T1 = 10 + 273.15 = 283.15
V2 = 1700
T2 = V2T1
T2 = (1700) (283.15) / 1275
T2 = 377.53 K
Volume = nRT/P
n = number of particles (moles)
R = universal gas constant (0.0821)
T = temperature (Kelvin)
P = pressure (atm)
(Assuming you have 1 mole of Helium in a chemical reaction) We would need to convert grams to moles: 12.0g He x 1 mol He/4 molar mass of He = 3 mol He
Convert Celsius to Kelvin: 100*C + 273.15 = 373.15 K
Now we can set up the equation for volume: (3mol)(0.0821)(373.15)/1.2atm = 76.6 L of Helium gas
Protons: 7
electrons: 7
neutrons: 7
