Answer:

Explanation:
From the question we are told that:
Distance 
Angle 
Force 
Generally the equation for magnitude of the stabilizing component of the brachialis force is mathematically given by



I think we will use the law of conservation of linear momentum;
M1V1 = M2V2
M1 = 4 kg (mass of the water balloon launcher)
V1=?
M2= 0.5 kg ( mass of the balloon)
V2 = 3 m/s
Therefore; 4 V1 = 0.5 × 3
4V1= 1.5
V1= 1.5/4
= 0.375 m/s
Answer:
0.426 L
Explanation:
Boyles law is expressed as p1v1=p2v2 where
P1 is first pressure, v1 is first volume
P2 is second pressure, v2 is second volume.
Given information
P1=96 kPa, v1=0.45 l
P2=101.3 kpa
Unknown is v2
Making v2 the subject from Boyle's law

Substituting the given values then

Therefore, the volume is approximately 0.426 L
x = V<em>x</em> * t
given V<em>x</em> = 10m/s n t = 3.53s
x = 10 * 3.53
= 35.3m