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bearhunter [10]
3 years ago
12

What is made of one type of atom​

Physics
1 answer:
umka21 [38]3 years ago
8 0

Any sample of an <em>ELEMENT</em> is made of only one type of atom.

Here are some elements:

-- Hydrogen, Helium, Neon

-- Carbon (lead in a pencil, also diamonds)

-- Oxygen, Nitrogen, Argon (All mixed together in air, but not hooked up with other atoms)  

Other elements you may have heard of:  

-- Silver, Gold, Copper, Iron, Lead, Aluminum, Silicon, Chlorine, Calcium, Titanium, Nickel, Tin, Platinum, Mercury, Radium, Uranium

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A train can travel at 300km/h. How long will it take to to travel 12.000km?
Leokris [45]

Answer:

Train will take 156 sec to travel 12km.

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3 years ago
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Electromagnetic waves all move at the same wave speed. which of these offer solutions to slowing them down select all that apply
Lelechka [254]

option c...have the waves move thru the vacuum or space

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3 years ago
With a thunderstorm brewing, an electric field of magnitude 2.0 × 102 newtons/coulomb exists at a certain point in the earth’s a
Aleks04 [339]

Answer:

The correct option is (b).

Explanation:

Given that,

Electric field, E=2\times 10^2\ N/C

We need to find the magnitude of the force on the electron as a result of the electric field.

We know that, the electric force is given by :

F=qE\\\\=1.6\times 10^{-19}\times 2\times 10^2\\\\F=3.2\times 10^{-17}\ N

So, the required force on the electron is equal to 3.2\times 10^{-17}\ N.

5 0
3 years ago
A compound microscope is made with an objective lens (f0 = 0.900 cm) and an eyepiece (fe = 1.10 cm). The lenses are separated by
Marizza181 [45]

Answer:

-252.52

Explanation:

L = Distance between lenses = 10 cm

D = Near point = 25 cm

f_o = Focal length of objective = 0.9 cm

f_e = Focal length of eyepiece = 1.1 cm

Magnification of a compound microscope is given by

m=-\frac{L}{f_o}\frac{D}{f_e}\\\Rightarrow m=-\frac{10}{0.9}\times \frac{25}{1.1}\\\Rightarrow m=-252.52

The angular magnification of the compound microscope is -252.52

6 0
3 years ago
A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.
labwork [276]

Answer:

9.4 m/s

Explanation:

According to the work-energy theorem, the work done by external forces on a system is equal to the change in kinetic energy of the system.

Therefore we can write:

W=K_f -K_i

where in this case:

W = -36,733 J is the work done by the parachute (negative because it is opposite to the motion)

K_i = 66,120 J is the initial kinetic energy of the car

K_f is the final kinetic energy

Solving,

K_f = K_i + W=66,120+(-36,733)=29387 J

The final kinetic energy of the car can be written as

K_f = \frac{1}{2}mv^2

where

m = 661 kg is its mass

v is its final speed

Solving for v,

v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.4 m/s

4 0
3 years ago
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