The magnitude of the unknown height of the projectile is determined as 16.1 m.
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Magnitude of the height</h3>
The magnitude of the height of the projectile is calculated as follows;
H = u²sin²θ/2g
H = (36.6² x (sin 29)²)/(2 x 9.8)
H = 16.1 m
Thus, the magnitude of the unknown height of the projectile is determined as 16.1 m.
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Answer:
-2.26×10^-4 radians
Explanation:
The solution involves a right angle triangle
Length is z while the horizontal is the height x
X^2+ 100^2=z^2
Taking the derivatives
2x(dx/dt)=Z^2(dz/dt)
Specific moments = Z= 200 ,X= 100sqrt3 and dx/dt= 11
dz/dt= 1100sqrt3/200 = 9.53
Sin a= 100/a
Taking derivatives in terms of t
Cos a(da/dt)=100/z^2 dz/dt
a= 30°
Cos (30°)da/dt= (-100/40000×9.5)
a= -2.26×10^-4radians
To solve this problem it is necessary to apply the concepts related to the Moment. The moment in terms of the Force and the time can be expressed as
F = Force
At the same time the moment can be expressed in terms of mass and velocity, mathematically it can be given as
Where
m = Mass
Change in velocity
Our values are given as
By equating the two equations we can find the Force,
Therefore, the net average force will be:
The negative symbol indicates that the direction of the force is upwards.
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