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olchik [2.2K]
1 year ago
8

In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system.

Kepler-12b, has a diameter that is 1.7 times that of Jupiter (RJupiter = 6.99 x 107 m), but a mass that is only 0.43 that of Jupiter (MJupiter = 1.90 x 1027 kg). Part A What is the value of g on this large, but low-density, world? Express your answer with the appropriate units. НА ? g= Value Units Submit Request Answer Provide Feedback
Physics
1 answer:
Marizza181 [45]1 year ago
6 0

3.86 m/s^2  is the value of gravity  on this large, but low-density, world.

given :

Kepler-12b

diameter= 1.7 times of Jupiter (R_Jupiter = 6.99 × 10^7 m),

mass = 0.43  Jupiter (M_Jupiter = 1.90 × 10^27 kg ).

g = GM/r^2

g = 6.67×10^-11 × 0.43×1.9×10^27/( 1.7×6.99×10^7)^2

g = 3.859 ~ 3.86 m/s^2

Gravity, also referred to as gravitation, is the unchanging force of attraction that binds all matter together in mechanics. It is by far the weakest known force in nature, so it has no effect on determining the internal properties of common matter.

On Earth, everything has weight, or a gravitational pull that is imposed by the planet's mass and proportional to the object's mass. A measure of the force of gravity is the acceleration that freely falling objects experience. At the surface of the Earth, gravity accelerates at a rate of about 9.8 meters per second. As a result, an object's speed increases during free fall by about 9.8 meters per second. At the Moon's surface, a freely falling body accelerates to about 1.6 m/s2.

To know more about  gravity visit : brainly.com/question/14428640

#SPJ4

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n 38 g rifle bullet traveling at 410 m/s buries itself in a 4.2 kg pendulum hanging on a 2.8 m long string, which makes the pend
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Answer:

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Explanation:

You can solve this problem by using the momentum conservation and energy conservation. By using the conservation of the momentum you get

p_f=p_i\\mv_1+Mv_2=(m+M)v

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By replacing you can find v:

(0.038kg)(410m/s)+0=(0.038kg+4.2kg)v\\\\v=3.67\frac{m}{s}

this value of v is used as the velocity of the total kinetic energy of the block of pendulum and bullet. This energy equals the potential energy for the maximum height reached by the block:

E_{fp}=E_{ki}\\\\(m+M)gh=\frac{1}{2}mv^2

g: 9.8/s^2

h: height

By doing h the subject of the equation and replacing you obtain:

(0.038kg+4.2kg)(9.8m/s^2)h=\frac{1}{2}(0.038kg+4.2kg)(3.67m/s)^2\\\\h=0.68m

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g A 2.3 kg block is attached to the spring, and it is released from rest 0.7 m from the spring's equilibrium position. Neglectin
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