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denpristay [2]
3 years ago
7

How many cookies does it take to reach the moon???!!

Physics
1 answer:
satela [25.4K]3 years ago
7 0

Answer: 5.89 x 10¹⁰ Oreos to reach the Moon.

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A rock is dropped from a sea cliff and hits the water 3.2s later. How high is the cliff? How long would it take sound to travel
Kruka [31]
<span>A rock is dropped from a sea cliff and hits the water 3.2s later. How high is the cliff?

t = sqrt(2y/g)
3.2 = sqrt(2y/9.81)
y = 50.23 m

</span><span>How long would it take sound to travel the same distance?
t = 50.23 / </span><span>343 m/s
t = 0.15 s

</span><span>How long would it take light to travel this distance? 
t = 50.23 / </span><span>299 792 458 m / s
t = 1.68x10^-7 s</span>
4 0
2 years ago
Which statement describes the general process of diffusion?
Murrr4er [49]
Diffusion is different from osmosis. Diffusion is when a solute passes through a semipermeable membrane inorder to reach equalibrium, while osmosis is water passing through a semipermeable membrane in order to reach equilibrium. Diffusion is when a higher concentration dilutes a lower concentration to reach its most equal state.
6 0
3 years ago
Read 2 more answers
Consider the following isobaric process for air, modelled as a Calorically Perfect Ideal Gas
Readme [11.4K]

These given conditions satisfy the second law of thermodynamics.

As the process is isobaric

So there will be a straight line of P= 200kPa in P-v and P-T planes

P1 = P2 = 100kPa

For perfect ideal gas, v-T plane:

v = (\frac{R}{P}) T

v_{1}  = (\frac{R}{P_{1} }) T_{1} = 287 × 500/200000 = 0.717 m³/kg

v_{2}  = (\frac{R}{P_{2} }) T_{2} = 287 × 600/200000 = 0.861m³/kg

As it is the calorically perfect gas

de = c_{v}dT

Integration on both sides

e2 - e1 = c_{v}(T2 - T1)

           = ( 716.5J/kg/K) (600-500)

           = 71650 J/kg

also,

Tds = de + Pdv

Tds = c_{v}dT +Pdv

For ideal gas

V = RT/P        

dv = Rdt/P - RTdp/P²

Tds = c_{v}dT + Rdt - RTdp/P

ds = (c_{v} + R)dT/T - RdP/P

ds = (c_{v} + c_{p} -c_{v})dT/T - RdP/P

ds = c_{p}dT/T - RdP/P

Integration on both sides

s2 - s1 = c_{p}ln (T2/T1) - R ln (P2/P1)

Since P is constant

s₂ - s₁ = c_{p} ln (T2/T1)

           = 1003.5 ln (600/500)

           = 1003.5 × 0.182

           = 182.95 J/kg/K

w = Pdv

w_{12} = P(v₂ - v₁)

     = 2,00,000 ( 0.861 - 0.717)

     = 28,800 J/kg

de = δq -δw

δq = de + δw

q₁₂ = (e₂ - e₁) +  w₁₂

    =  71,650 + 28,800 = 1,00,450 J/kg

Now in this process, the gas is heated from 500 K to 600 K. We would expect at a minimum that the surroundings were at 600 K.

Let’s check for second law satisfaction.

s₂ - s₁ ≥ q₁₂ / Tₓ

182.95 ≥ 1,00,450 / 600 K

182.95 J/kg/K ≥ 167.41 J/kg/K

Hence this condition satisfies the second law of thermodynamics

Learn more about laws of thermodynamics here brainly.com/question/13164851

#SPJ1

3 0
1 year ago
A motorcycle travels at 6.0 m/s. After 3.0 seconds, the motorcycle travels at 15.0 m/s.
Dmitriy789 [7]

Answer:

a=?

Vf=15.0m/s

Vi=6.0m/s

t=3.0s

a=Vf-Vi/t

a=15.0-6.0/3.0

a=9/3

a=3m/s^2

Explanation:

3 0
3 years ago
Which of the following would cause the greatest increase in gravitational
SIZIF [17.4K]

Explanation:

To be honest, it depends how far away the object is. half of 2 is 1, half of 1000000 is 500000 soo, but I would say doubling the mass.

3 0
2 years ago
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