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IceJOKER [234]
3 years ago
14

Help ... plz

Physics
1 answer:
Alona [7]3 years ago
3 0

<u>Benefits of strength and muscular endurance exercises and two examples:</u>

Of several purposes, muscle strength and endurance are beneficial, like as follows

  • increasing potential to do things such as doing daily routine work
  • carrying boxes or wood cutting before getting exhausted
  • reducing the risk of injury
  • helping you to maintain a healthy body weight
  • contributing to healthier muscles and bones
  • enhancing morale and feeling about yourself.

The two examples for strength and muscular endurance exercises are: Plank and Body weight squats.

Squats shape the human body part which is used to sit (butt) and entire body, reduce fat, strengthen posture, increase blood circulation, boost your flexibility.  

While plank helps to reinforce the heart, hikes metabolism, decline back pain by supporting backbone, improved joint health, balance mood and relieved stress.

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A neighbor's child wants to go to a neighborhood carnival to experience the wild rides. The neighbor is worried about safety as
seraphim [82]

Answer:

No, the ride is not safe

Explanation:

From the diagram attached, it is seen that

\sum f_{y} = 0

\tau cos \theta - W = 0................(1)

\sum f_{x} = 0

-ma + \tau sin \theta = 0.......(2)

a = w^{2} r

From the diagram, r = Lsin \theta

a = w^{2} L sin \theta

w = \frac{2\pi }{T}

a = \frac{4\pi ^{2}L sin \theta }{T^{2} }............(3)

Put (3) into (2)

\tau sin \theta = \frac{4\pi ^{2}m L sin \theta }{T^{2} }

\tau  = \frac{4\pi ^{2}m L  }{T^{2} }

w = weight of chair + weight of child = 50 + 10 = 60 lb

g = 32 ft/s²

m = w/g = 60/32 = 1.875

L = 30 ft

T = 3 secs

\tau  = \frac{4\pi ^{2}*1.875*30  }{0.3^{2} }

\tau = 246.74 lbs

since 246.74 lbs > 200 lbs, it is not safe because the stationary chair will creak

6 0
3 years ago
Read 2 more answers
Which mass is undergoing to the greatest amount of acceleration ??
lina2011 [118]

Answer:

Option (3)

Explanation:

Formula used to calculate acceleration is,

F = ma

Where F = force exerted on a mass

m = mass

a = acceleration due to force exerted on the mass

Option (1),

When F = 100 N and m = 100 kg

100 = 100a

a = 1 m per sec²

Option (2)

For F = 1 N and m = 100 kg

1 = 100a

a = \frac{1}{100}

a = 0.01 m per sec²

Option (3)

For F = 100 N and m = 1 kg

100 = 1(a)

a = 100 m per sec²

Option (4)

For F = 1 N and m = 1 kg

1 = 1(a)

a = 1 m per sec²

Therefore. acceleration in Option (3) is the maximum.

4 0
4 years ago
The stars in the sky are organized into groups of stars called constellations which appear near each other in the sky but are no
bezimeni [28]

Answer:

The International Astronomical Union (IAU)  has accepted 88 constellations in the sky.

Explanation:

Constellations has been used since the beginnings of civilizations and each one of them named them as they considered appropiate. It means Greeks' constellations were different than the ones described by Chinese, so it was necessary to gather all these constellations and make a great record with all of them, but there was a problem: Some constellations from different civilizations overlaped because they shared the same stars. There was necessary to put some order on this and that is when in 1922 the International Astronomical Union (IAU) defned a set of 88 moderm constellations  that would become the international standard to look at the night sky. Each one of them is unique and does not share stars with the other constellations.  

6 0
3 years ago
A miner finds a small mineral fragment with a volume of 5.74 cm^3 and a mass of 28.7 g. What is the density of that mineral frag
statuscvo [17]
P=M÷V
p=28.7÷5.74
p=5

The density is 5.
8 0
3 years ago
Read 2 more answers
A converging lens has a focal length of 20 cm. An object 1 cm tall is placed 10 cm from the center of the lens. What is the heig
SCORPION-xisa [38]

Answer: 2 cm

Explanation:

Given , for a converging lens

Focal length : f=20\ cm

Height of object : h=1\ cm

Object distabce from lens : u=-10\ cm

Using lens formula: \dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}, we get

\dfrac{1}{20}=\dfrac{1}{v}+\dfrac{1}{10}, where v = image distance from the lens.

On solving aboive equation , we get

\dfrac{1}{v}=\dfrac{1}{20}-\dfrac{1}{10}=\dfrac{1-2}{20}=\dfrac{-1}{20}\Rightarrow\ v=-20\ cm

Formula of Magnification : m=\dfrac{v}{u}=\dfrac{h'}{h} , where h' is the height of image.

Put value of u, v and h in it , we get

\dfrac{-20}{-10}=\dfrac{h'}{1}\\\\\Rightarrow\ h'=2\ cm

Hence, the height of the image is 2 cm.

3 0
3 years ago
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