1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
otez555 [7]
3 years ago
9

Positive Charge Q is distributed uniformly along the x-axis from x=0 to x=a. A positive point charge q is located on the positiv

e x-axis at point x-atr, a distance r to the right from the end of Q. (a) Using integral calculus, calculate the elect field produced by the charge distribution all points x > a. (b) What is the force on the small charge q (c) If/>>a, what is the force on q?
Physics
1 answer:
deff fn [24]3 years ago
6 0

Answer:

 electric field E = - k Q (1 /r(r-a)), force    F = - k Q qo / r (r-a) and force for r>>a    F ≈ - k Q qo / r²

Explanation:

You are asked to find the electric field of a continuous charge distribution, so we must use the equation

       

           E = k ∫dp /r²

Where k is the Coulomb constant that is worth 8.99 10⁹ N m² / C², r is the distance between the load distribution and the test charge, in this case everything is on the X axis.

We must find the charge differential (dq), let's use that uniformly distributed and create a linear charge density

          λ = q / x

As it is constant, we can write it based on differentials

         λ = dq / dx

         dq = λ dx

We already have all the terms, let's  integrate enter its limits, lower the distance from the left end of the distribution to the test charge (x = r) and the upper limit that is the distance from the left end of distribution to the test load ( x = r - a) where r> a

         E = k ∫ λ dx / x²

         E = k la (- 1 / x)

Let's get the negative sign from the parentheses

         E = - k λ (1 / x)

         E = - k λ (1 /(r-a)  -1 /r) = - k λ [a / r (r-a)]

Let's change the charge density with the value of the total charge λ = Q / a

         E = - k Q/a  [a / r (r-a)]

         E = - k Q (1 /r(r-a))

b) We calculate the force.  

         F = E qo

         F = - k Q qo / r (r-a)

c) the force for charge porbe very far r >> a. In this case we can take r from the parentheses and neglect (a/r)

         F = - k Qqo / r² (1 -  a/r)

         F ≈ - k Q qo / r²

You might be interested in
What are two ways in which ultrasound technology produces images
arsen [322]
Fetal and ophthalmic
6 0
3 years ago
The right ventricle transports oxygenated blood to the lungs.
juin [17]

Answer: False

Explanation: The circulatory system of the body consists of the heart, blood vessels and blood. The deoxygenated blood from the body is carried to the heart.

Here, the deoxygentaed blood is converted into oxygenated by removing carbon dioxide from them and making it oxygenated.

The impure blood from the body is collected by the right ventricle and transported to the lungs for purification and then transported to the body.

5 0
3 years ago
Read 2 more answers
Rocks from volcanoes are used by scientists to study the interior of the earth<br><br>TRUE OR FALSE​
cupoosta [38]
I think it’s false bc A volcano is not in the interior of the earth
6 0
3 years ago
Read 2 more answers
______ 4. Justin was creating a chart comparing the potential energy between charged particles and the potential energy of magne
fredd [130]

Answer:

The correct option is;

A. The potential energy between both like charges and like poles increases as they move closer together

Explanation:

Here we have that when we move the like poles of two bar magnets close to each other, there is an increased resistance in the continuing motion, therefore for each extra gap closer achieved, there is an increase in potential energy

Similarly, when two like charges are brought closer together, the potential energy, or the energy available to push the two like charges apart increases charge as the as the charges are brought closer together

Therefore, the correct option is the potential energy between both like charges and like poles increases as they move closer together.

4 0
3 years ago
4. A 1,000-kilogram satellite completes a uniform circular orbit of radius 8.0 x 10 meters as
lesantik [10]

Answer:

Zero

Explanation:

The work done by a force on an object is given by:

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and the displacement of the object

In this situation, the force is the force of gravity acting on the satellite. This force always points towards the centre of the trajectory, so it is always perpendicular to the direction of motion of the satellite (since the orbit is circular), so \theta=90^{\circ} and cos \theta =0. Therefore, the work done by gravity is also zero.

5 0
3 years ago
Other questions:
  • HELP ASAP!!! So stressed! :(
    6·1 answer
  • An artificial satellite circles the Earth in a circular orbit at a location where the acceleration due to gravity is 6.25 m/s2.
    10·2 answers
  • What are the functions of the female reproductive system?
    5·1 answer
  • Would happen if the rate that Dark Energy is expanding the universe would increase, but if gravity increased with it so the grea
    7·1 answer
  • Jay rides his 2.0-kgkg skateboard. He is moving at speed 5.8 m/sm/s when he pushes off the board and continues to move forward i
    14·1 answer
  • (a) When we rub a plastic rod witha piece of fur, --------------transfer from ----------------to the ------------. In the result
    7·1 answer
  • If the specific heat of a metal is 0.850 J/g °C, what is its atomic weight?
    12·2 answers
  • An 84% efficient single pulley is used to lift a 230 kg piano 3.5 m. How much work must be input?
    10·1 answer
  • What is drag ? and which is the greatest friction ?
    15·2 answers
  • a nitrogen laser generates a pulse containing 10.0 mj of energy at a wavelength of 340.0 nm. how many photons are in the pulse?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!