All categories

3 years ago

The initial explanation for a phenomenon prior to experimentation is called a:

Chemistry

2 answers:

maks197457 [2]3 years ago

5 0

Answer: Hypothesis

Explanation: Hypothesis is a kind of idea that has been put forward prior to experimentation and whose results are not out yet.

The laws makes the theory then there are some rules which are needed to be followed in order to make the most out of the experiments. Then prior to the experiments , there comes the hypothesis whis the explanation of the work and which would be tested through the experiments.

lord [1]3 years ago

3 0

The explanation for a phenomenon is a hypothesis something happened that you sure that was going to happen

You might be interested in

Calculate the mass (g) of each product formed when 43.82 g of diborane (B₂H₆)

guajiro [1.7K]

Stoichiometry:

The area of study in chemistry concerned with the quantities of chemical species produced or required for a given chemical reaction is stoichiometry. The stoichiometric coefficients of the balanced chemical equation are often used to relate the amounts of substances to one another.

Evaluation :

The balanced chemical equation for the reaction is given as follows:

$B_{2} H_{6} + 6H_{2} O$ → $2H_{3} BO_{3} + 3H_{2}$

By using the molar mass of the given chemical species, along with the stoichiometric coefficients of the balanced chemical equation, we determine the mass of each product as:

43.82 g $B_{2} H_{6}$ × $\frac{1 Mol B_{2} H_{6} }{27.66 g}$ × $\frac{3molH_{2} }{1 molB_{2}H_{6} }$ × $\frac{2g}{1 mol H_{2} } = 9.51 g H_{2}$

43.82 g $B_{2} H_{6}$ × $\frac{1 mol B_{2} H_{6} }{27.66 g}$ × $\frac{1 mol H_{3}BO_{3} }{1 mol B_{2} H_{6} }$ × $\frac{61.8g}{1 mol H_{3} BO_{3} } = 196 gH_{3} BO_{3}$

Learn more about chemical reaction :

brainly.com/question/1893305

#SPJ4

6 0

2 years ago

What is a membrane?

9966 [12]

B I think, it has layers that protects the cells nucleus

3 0

3 years ago

The ratio of nitrogen to oxygen by mass in NO is 7.0:8.0. Identify the ratio of nitrogen to oxygen by mass in NO2 and N2O7 .

Rus_ich [418]

This problem is providing the ratio of nitrogen to oxygen by mass in nitrogen monoxide, NO, as 7.0:8.0 and asks for the same ratio but in NO₂ and N₂O₇. After doing the calculations, the results are 7.0:16.0 and 1.0:4.0 respectively.

<h3>Mass ratios:</h3>

In chemistry, one can calculate the mass ratios in chemical formulas according to the atomic mass of each atom. In such a way, one knows the mass ratio of nitrogen to oxygen in NO is 7.0:8.0 because we divide the atomic mass of nitrogen by oxygens:

$\frac{14}{16}=\frac{7.0}{8.0}$

Now, for chemical formulas with subscripts, one must multiply the atomic mass of the element by the subscript in the formula, which is the case of NO₂ and N₂O₇ as shown below:

$NO_2:\frac{14}{16*2}=\frac{14}{32} =\frac{7.0}{16.0} \\
\\
N_2O_7:\frac{14*2}{16*7}=\frac{28}{112} =\frac{1.0}{4.0}$

Therefore, the results for NO₂ and N₂O₇ are 7.0:16.0 and 1.0:4.0 respectively

Learn more about atomic masses: brainly.com/question/5566317

3 0

3 years ago

Pt 2. Chem Reactions 50 PTS

Dahasolnce [82]

The red colour is the limiting reactant.

Red-blue colour ball and two white balls attached together are reactants.

Red-blue colour ball and two white and one red colour ball attached to each other are products.

<h3>What is a limiting reagent?</h3>

The reactant that is entirely used up in a reaction is called a limiting reagent.

A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products.

A product is a substance that is present at the end of a chemical reaction.

Hence,

The red colour is the limiting reactant.

Red-blue colour ball and two white balls attached together are reactants.

Red-blue colour ball and two white and one red colour ball attached to each other are products.

Learn more about limiting reagents here:

brainly.com/question/26905271

#SPJ1

6 0

2 years ago

How many grams are in a sample of 0.55 mol of K?

Katyanochek1 [597]

The equation you use here is
mass =moles x Mr

So:
Moles of K - 0.55mol
Mr of K - 39.1

Mass= 0.55x39.1 =21.505g

4 0

3 years ago