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Gemiola [76]
2 years ago
15

5. The atmosphere is heated both by the Sun and by the Earth's surface. Water radiates heat differently than land, so the air te

mperature over the ocean is usually different than the air temperature over land.
The difference in air temperature over land compared to over water causes convection currents in the atmosphere. How would a person at the beach experience these convection currents?
They would feel the heat of the Sun.
They would feel that the water is cold.
They would feel that the sand is hot.
They would feel wind as the air moves.
Physics
2 answers:
solong [7]2 years ago
4 0

NO its they would feel wind as the air moves. Because i had this question


Ierofanga [76]2 years ago
3 0
<span>They would feel that the water is cold.

</span> The atmosphere is heated both by the Sun and by the Earth's surface. Water radiates heat differently than land, so the air temperature over the ocean is usually different than the air temperature over land. <span>
The difference in air temperature over land compared to over water causes convection currents in the atmosphere. How would a person at the beach experience these convection currents? 
</span>They would feel that the water is cold.

NOT:
They would feel the heat of the Sun.
They would feel that the sand is hot.
<span>They would feel wind as the air moves.</span>
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The temperature of air changes from 0 to 10°C while its velocity changes from zero to a final velocity, and its elevation change
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Answer:

Final velocity = 119.83 m/s

Final elevation = 731.9 m

Explanation:

We are told that temperature of air changes from 0 to 10°C

Thus;

Change in temperature; ΔT = 10 - 0 = 10°C

Also, its velocity changes from zero to a final velocity. Thus;

v1 = 0 m/s

v2 is unknown

Also, its elevation changes from zero to a final elevation.

So, z1 = 0 and z2 is unknown

Now, we want to find v2 and z2 when the internal, kinetic and potential energy are equal.

Thus Equating the formula for both kinetic and internal energy gives;

½m(v2² - v1²) = mc_v•ΔT

m will cancel out and v1 is zero to give;

v2² = 2c_v•ΔT

v2 = √(2c_v•ΔT)

Where c_v is specific heat of constant volume of air with a constant value of 718 J/Kg.K

Thus;

v2 = √(2 × 718 × 10)

v2 = √14360

v2 = 119.83 m/s

To find z2, we will equate potential energy formula to that of the internal energy.

Thus;

mg(z2 - z1) = mc_v•ΔT

m will cancel out and since z1 is zero, then we have;

z2 = (c_v•ΔT)/g

z2 = 718 × 10/9.81

z2 = 731.9 m

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The volume of the system remains constant,

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