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mezya [45]
3 years ago
10

calculate the heat required in joules to convert 18.0 grams of water ice at a temperature of -20 c to liquid water at the normal

boiling point of water given specific heat of ice 2.09
Chemistry
1 answer:
KIM [24]3 years ago
7 0

Answer:

Explanation:

Heat required to convert ice to ice at 0⁰C

= mass x specific heat x rise in temperature

= 18 x 2.09 x 20

= 752.4 J .

heat required to convert ice at 0⁰C to water at 0⁰C

mass x latent heat of fusion

= 18 x 336

= 6048 J

Heat required to increase the temperature of water to 100⁰C

= 18 x 4.2 x 100

= 7560 J

Total heat required

7560 + 6048 + 752.4

= 14360.4 J

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