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atroni [7]
3 years ago
13

Suppose that a constant force is applied to an object. newton's second law of motion states that the acceleration of the object

varies inversely with its mass. a certain force acting upon an object with mass 2 kg produces an acceleration of 38 /ms2 . if the same force acts upon another object whose mass is 19 kg , what would this object's acceleration be?
Physics
1 answer:
amid [387]3 years ago
3 0

Newton’s second law states that force is the product of mass and acceleration. This is expressed mathematically as:

F = m * a

Where F = force, m = mass, a = acceleration

Since in the given problem, the force is constant or same force is acting upon two objects. Therefore we can simply equate the expression m * a of the 2 objects.

m1 * a1 = m2 * a2

Where m1 = 2 kg, a1 = 38 m/s^2, m2 = 19 kg. Therefore finding for a2:

2 kg * 38 m/s^2 = 19 kg * a2

<span>a2 = 4 m/s^2     (ANSWER)</span>

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It takes a minimum distance of 57.46 m to stop a car moving at 13.0 m/s by applying the brakes (without locking the wheels). Ass
vivado [14]

Answer:

The minimum stopping distance when the car is moving at

29.0 m/sec = 285.94 m

Explanation:

We know by equation of motion that,

v^{2}=u^{2}+2\cdot a \cdot s

Where, v= final velocity m/sec

u=initial velocity m/sec

a=Acceleration m/Sec^{2}

s= Distance traveled before stop m

Case 1

u=  13 m/sec, v=0, s= 57.46 m, a=?

0^{2} = 13^{2}  + 2 \cdot a \cdot57.46

a = -1.47 m/Sec^{2} (a is negative since final velocity is less then initial velocity)

Case 2

u=29 m/sec, v=0, s= ?, a=-1.47 m/Sec^{2} (since same friction force is applied)

v^{2} = 29^{2}  - 2 \cdot 1.47 \cdot S

s = 285.94 m

Hence the minimum stopping distance when the car is moving at

29.0 m/sec = 285.94 m

4 0
3 years ago
What best describes an impulse acting on an object? the net force on an object divided by the time of impact the velocity of an
Leona [35]

Answer:

ok so

Explanation:

Im not sure rn but ill get back to you.

7 0
2 years ago
A ferry is travelling at 10 m/s relative to the river towards the south. The river is flowing at 2 m/s relative to
mixer [17]

Answer:

11 m/s south

Explanation:

The velocity of the passenger relative to the river bank is equal to the velocity of the passenger relative to the ferry, plus the velocity of the ferry relative to the river, plus the velocity of the river relative to the river bank.

v_passenger,bank = v_passenger,ferry + v_ferry,river + v_river,bank

If we take north to be positive and south to be negative:

v = 1.0 m/s + (-10 m/s) + (-2 m/s)

v = -11 m/s

v = 11 m/s south

8 0
3 years ago
The temperature at 8:00
musickatia [10]
Change in temperature = final temperature - Initial temperature 
Δt = t₂ - t₁
Δt = 17 - (-6)
Δt = 17 + 6 = 23 f

In short, Your Answer would be Option D

Hope this helps!
6 0
3 years ago
A metal spoon can be classified as which of the following
LenaWriter [7]
What are the options
4 0
3 years ago
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