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3 years ago

Q1. On the Kelvin scale water freezes at 273 K and boils at 373 K. True False

Chemistry

1 answer:

faust18 [17]3 years ago

8 0

Answer:

True

Explanation:

Water boils at 373 kelvins. ... Absolute zero is –273.15° C or –459.67° F. The "size" of a one degree change in temperature is exactly the same in the Celsius and Kelvin scales, so the freezing point of water is at a temperature of 273.15 kelvins (that is, 273.15 degrees above absolute zero

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A solution contains one or more of the following ions: Ag + , Ca 2 + , and Co 2 + . Ag+, Ca2+, and Co2+. Lithium bromide is adde

Eva8 [605]

Answer:

Since with LiBr no precipitation takes place. So, Ag+ is absent

When we add Li2SO4 to it, precipitation takes place.

Ca2+(aq) + SO42-(aq) ----> CaSO4(s) ...Precipitate

Thus, Ca2+ is present.

When Li3PO4 is added, again precipitation takes place.Reaction is:

Co2+(aq) + PO43-(aq)---->Co3(PO4)2(s) ... Precipitate

A. Ca2+ and Co2+ are present in solution

B. Ca2+(aq) + SO42-(aq) ----> CaSO4(s)

C. 3Co2+(aq) + 2PO43-(aq)---->Co3(PO4)2(s)

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3 years ago

How to use molar mass

ruslelena [56]

Explanation:

the molar mass of a compound can be caucaleted by adding the standar atomic masses.

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3 years ago

Read 2 more answers

What is a property of a solution with a high pH? Select all that apply. *

Lena [83]

Answer:

Bases (solutions with a high pH) feel slipper, have an -OH group, and are corrosive.

8 0

3 years ago

The total volume of seawater is 1.5 x 1021L .Assume that seawater contains 3.1 percent sodium chloride by mass and that its dens

son4ous [18]

Answer:

Mass in kg = 4.7*10^19 kg

Mass in tons = 5.2*10^16 tons

Explanation:

Given:

Total volume of sea water = 1.5*10^21 L

Mass % NaCl in seawater = 3.1%

Density of seawater = 1.03 g/ml

To determine:

Total mass of NaCl in kg and in tons

Calculation:

Unit conversion:

1 L = 1000 ml

The volume of seawater in ml is:

$=\frac{1.5*10^{21}L*1000ml }{1L} =1.5*10^{24} ml$

$Mass\ seawater = Density*volume = 1.03g/ml*1.5*10^{24} ml=1.5*10^{24}g$

$Mass\ NaCl\ in\ seawater = \frac{3.1}{100}*1.5*10^{24} g=4.7*10^{22} g$

To convert mass from g to Kg:

1000 g = 1 kg

$Mass\ seawater(kg) = \frac{4.7*10^{22}g*1kg }{1000g} =4.7*10^{19} kg$

To convert mass from g to tons:

1 ton = 9.072*10^6 g

$Mass\ seawater(tons) = \frac{4.7*10^{22}g*1ton }{9.072*10^{6}g } =5.2*10^{16} tons$

5 0

3 years ago

2. A reaction vessel is charged with hydrogen iodide, which partially decomposes to molecular hydrogen and iodine:2HI (g) H2(g)

Deffense [45]

Answer:

The value of Kp at this temperature is 7.44*10⁻³

Explanation:

Chemical equilibrium is established when there are two opposite reactions that take place simultaneously at the same speed.

For the general chemical equation for a homogeneous gas phase system:

aA + bB ⇔ cC + dD

where a, b, c and d are the stoichiometric coefficients of compounds A, B, C and D, the equilibrium constant Kp is determined by the following expression:

$Kp=\frac{P_{C} ^{c} *P_{D} ^{d} }{P_{A} ^{a} *P_{B} ^{b} }$

Where Px is the partial pressure of each of the components once equilibrium has been reached and they are expressed in atmospheres. The equilibrium constant Kp depends solely on temperature and is dimensionless.

In the case of the reaction:

2 HI (g) ⇔ H₂ (g) + I₂ (g)

the equilibrium constant Kp is determined by the following expression:

$Kp=\frac{P_{H_{2} } *P_{I_{2} } }{P_{HI} ^{2} }$

The system comes to equilibrium at 425 °C, and

PHI = 0.794 atm
PH2 = 0.0685 atm
PI2 = 0.0685 atm

Replacing:

$Kp=\frac{0.0685*0.0685}{0.794^{2} }$

Kp=7.44*10⁻³

The value of Kp at this temperature is 7.44*10⁻³

4 0

3 years ago