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ExtremeBDS [4]
4 years ago
11

If an object weighs 40N, calculate the mass (gravity = 9.8m/s^2)​

Physics
1 answer:
Elan Coil [88]4 years ago
4 0

Answer:

4.08 kg

Explanation:

We can apply the Newton's second law of motion to find the mass of this object:

F=ma,

where m is mass, and a is acceleration, which is substituted by g here. Now, plugging given numbers in the equation, we have

40=m\cdot9.8.

Solving for mass, we have

m=\frac{40}{9.8}\\=4.08 \;\text{kg}.

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saveliy_v [14]

Answer:

The Earth would increase in volume.

Explanation:

Earth's crust is less dense than the mantle.

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4 0
3 years ago
A laser beam is incident on two slits with a separation of 0.180 mm, and a screen is placed 5.05 m from the slits. If the bright
gladu [14]

Answer:

The answer is "530 nm".

Explanation:

d=0.180 \ nm=0.180 \times 10^{-3} \ m\\\\L= 5.05\ m\\\\\Delta y=  1.62\ cm= 1.62 \times 10^{-2} \ m\\\\

Using formula:

\Delta y=\frac{\lambda L}{d}\\\\\lambda =\frac{d\Delta y}{L}\\\\

  =\frac{0.180 \times 10^{-3} \times  1.62 \times 10^{-2} }{5.05}\\\\=5.30 \times 10^{-9} \times  \frac{1 \ nm}{10^{-9} \ m}\\\\=530 \ nm

6 0
4 years ago
The green light from a traffic signal occurs at a wavelength of 522 nm. What is the frequency of this radiation?
kumpel [21]

Answer:

5.75\times 10^{14}Hz

Explanation:

We are given that

Wavelength of green light=522nm=522\times 10^{-9}m

1nm=10^{-9} m

We have to find the frequency of this radiation.

We know that

Velocity of light=3\times 10^8m/s

\nu=\frac{c}{\lambda}

Where \nu=Frequency of radiation

c=Velocity of light

\lambda=Wavelength of radiation

Using the formula

\nu=\frac{3\times 10^8}{522\times 10^{-9}}=5.75\times 10^{14}Hz

Hence, the frequency of radiation=5.75\times 10^{14}Hz

3 0
3 years ago
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A football player kicks a ball with an initial velocity of 15 m/s at an angle of 43° above the horizontal. Approximately,
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Hi there!

The vertical component is the SINE of the velocity vector.

Thus:

v_y = vsin\theta

Plug in the givens:

v_y = 15sin(43) = \boxed{10.23 m/s}

6 0
3 years ago
A person leaves a starting point at a constant speed of 4 mi./s and walks for four seconds the person then stops for two seconds
frutty [35]
What's the question?
5 0
3 years ago
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