Answer:
C. 1.35
Explanation:
2NH3 (g) <--> N2 (g) + 3H2 (g)
Initial concentration 2.2 mol/0.95L 1.1 mol/0.95L 0
change in concentration 2x x 3x
-0.84 M +0.42M +1.26M
Equilibrium 1.4 mol/0.95L=1.47M 1.58 M 1.26 M
concentration
Change in concentration(NH3) = (2.2-1.4)mol/0.95 L = 0.84M
Equilibrium concentration (N2) = 1.1/0.95 +0.42=1.58 M
Equilibrium concentration(NH3) = 1.4/0.95 = 1.47M
K = [N2]*{H2]/[NH3] = 1.58M*1.26M/1.47M = 1.35 M
Answer:
Diluted
Explanation:
Imagine having a sugar filled water (like a lot of them). This is a strong solution.
You can dilute this by adding more water to make it less concentrated.
Answer:
99.3%
Explanation:
The percent by mass of the solute can be expressed as:
- % mass =
* 100%
And for this problem:
- Mass of Solute = Mass of sodium lithium chloride = 29 g
- Mass of Solvent = Mass of Water
So to calculate the percent by mass first we need to <u>calculate the mass of water</u>, to do so we use its<em> density</em> (1 g/L):
- 202 mL is equal to (202/1000) 0.202 L.
Density water = mass water / volume
- 1 g/L = mass water / 0.202 L
Now we have all the data required to <u>calculate the % mass:</u>
- % mass =
* 100 % = 99.3%