Answer: 401.4g
Explanation:
The mass can be calculated by using the following mathematical expression for Moles ,which is:
Moles = Mass / Molar Mass
From the question given, Moles = 1.72, Molar mass of BaSO4 = 233.38g/mol, Mass =?
Making 'Mass' the subject of formula, we get:
Mass = Molar mass x Moles
= 233.38 x 1.72 = 401.4g
O1Fl2
1. Assume an 100g sample, so the percentage will stay the same
2. Covert each element into their molar mass
29.6/16.00=1.8 mols of O
70.4/19.00=3.7 mols of Fl
3. Divide both by the smallest value of mol
1.8/1.8=1 O
3.7/1.8=2 Fl
4. Write the empirical formula:
O1Fl2
Answer:
-490.7 K
Explanation:
Given:
[Ni^2+]= 0.4 M
[Pb^2+]=0.002 M
∆V= -0.012 V
VNi= -0.250V
VPb= -0.126V
F= 96500 C
R= 8.314 JK-1 mol-1
n= 2
From
T= -nF/R [∆V-(VNi-VPb)/ln [Pb2+]/[Ni2+]]
T= 2(96500)/8.314[ (-0.012) -(-0.250) - (-0.126))/ln[0.002]/[0.4]
T= 23213.856(0.112/(-5.298))
T= -490.7 K
I’m pretty sure it’s in a group (column) of the period table. Hope this helps :)))
