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SVETLANKA909090 [29]
3 years ago
13

The engine in a small airplane is specified to have a torque of 500 N⋅m . This engine drives a 2.4- m -long, 40 kg single-blade

propeller.On startup, how long does it take the propeller to reach 2000 rpm ?
Physics
1 answer:
Mariulka [41]3 years ago
5 0

Answer:

8.04 second

Explanation:

torque = 500 Nm

Length of blade, L = 2.4 m

mass of blade, m  40 kg

initial angular velocity, ωo = 0  rad/s

frequency, f = 2000 rpm = 2000 / 60 rps

final angular velocity, ωf = 2 x π x 2000 / 60 = 209.33 rad/s

Moment of inertia of the blade,

I = \frac{1}{12}mL^{2}

I = \frac{1}{12}\times 40\times 2.4^{2}

I = 19.2 kg m^2

Torque = Moment of inertia x angular acceleration

500 = 19.2 x α

where, α be the angular acceleration

α = 26.04 rad/s^2

Use first equation of motion

ω = ωo + αt

where t is the time taken by the propeller to reach 2000 rpm.

209.33 = 0 + 26.04 x t

t = 8.04 second

Thus, the time taken by the propeller is 8.04 second.

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This is a simple application of Newton's Law of Universal Gravitation. The force of gravity is inversely proportional to the distance between the two centers of mass. We don't need to know the mass of earth or the test mass to solve this, because we'll be setting up a proportionality, which means that all controlled variables can be expressed as a proportionality constant which will eventually cancel. <span>

Set up the following proportionality equation from Newton's Universal Gravitation: 
F = k/d²; where k is the constant of proportionality

Plug in values for F and d, making two equations: 
(9.803 N) = k/r²; where r is the radius of earth, and 
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Divide one by the other, and you get: 
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Solve for h: 
√(9.803 / 9.792) = (r+h) / r 
r √(9.803 / 9.792) = r + h 
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<span>h ≈ 3.58 km</span></span>

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4 years ago
If a pulley system with an actual mechanical advantage of 2,000,000 is used in lifting a 2,000 lb. car, what effort would be nee
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What is the main difference between a theory and a law?
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Determine the initial velocity of the ball if it reaches a height of 15 meters.
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Answer:

the initial velocity of the  ball is 17.14 m/s

Explanation:

Given;

maximum height reached by the ball, h = 15 m

let the initial velocity of the ball = u

at maximum height, the final velocity of the ball is zero, v = 0

The initial velocity of the ball is calculated by using the following upward motion kinematic equation;

v² = u² - 2gh

0 = u² - 2(9.8 x 15)

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19) A child on a sled starts from rest at the top of a 15.0° slope. If the trip to the bottom takes 15.2 s,
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Answer: 288.8 m

Explanation:

We have the following data:

t=15.2 s is the time it takes to the child to reach the bottom of the slope

V_{o}=0 is the initial velocity (the child started from rest)

\theta=15\° is the angle of the slope

d is the length of the slope

Now, the Force exerted on the sled along the ramp is:

F=ma (1)

Where m is the mass of the sled and a its acceleration

In addition, if we draw a free body diagram of this sled, the force along the ramp will be:

F=mg sin \theta (2)

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Then:

ma=mg sin \theta (3)

Finding a:

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a=2.5 m/s^{2} (6)

Now, we will use the following kinematic equations to find d:

V=V_{o}+at (7)

V^{2}=V_{o}^{2}+2ad (8)

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Finding V from (7):

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V=38 m/s (10)

Substituting (10) in (8):

(38 m/s)^{2}=2(2.5 m/s^{2})d (11)

Finding d:

d=288.8 m

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