Answer:
The correct statements that you must check are:
- The oxygen atom has a greater attraction for electrons than the hydrogen atom does (second statement).
- The electrons of the covalent bond are not shared equally between the hydrogen and oxygen atoms (fourth statement).
Explanation:
Electronegativity is the relative ability of an atom to pull the electrons in a covalent bond.
Hydrogen has an electronegativity of 2.20 and oxygen has 3.44. That means that oxygen attracts the electrons more strongly than hydrogen does (second statement).
As consequence, the electrons in the covalent bond H - O of water are not shared equally (fourth statement): the electron density will be higher around the O atoms.
Of course, this discards the statement telling that hydrogen atom attracts electrons much more strongly than the oxygen atom, and the statement telling that hydrogen and oxigen have same electronegativity.
Such difference in electron densities creates a dipole moment, so you discard the last statement (that the water dipole moment is equal to zero).
hydrochloric Acid Carbondale
Answer:
Reflection/change of direction
Explanation:
When the light of the laser hits the glass of water, it reflects and goes another direction. It's basically just a change of direction. The light is mostly in the glass of water and just some reflecting off of it.
Answer:
56 g of sucrose is the mass needed
Explanation:
Formula for osmotic pressure → π = M . R . T
8 atm = M . 0.082 L.atm/mol.K . 290 K
8 atm / (0.082 L.atm/mol.K . 290 K) = M → 0.336 mol/L
Let's determine the mass of sucrose that represents 0.336 mol
0.336 mol . 342 g / 1mol = 114.9 g
This is the mass that corresponds to 1L of solution, but we have 0.488 L
Solution density = 1 g/mL → 488 g are contained in 488 mL.
488 mL . 1L / 1000 mL = 0.488 L
Let's make a rule of three:
1L is the volume for 114.9 g of sucrose
In 0.488 L of volume, we need a mass of (0.488L . 114.9 g) 1L = 56 g
Answer: The volume of oxygen at STP is needed for complete given combustion is 1121.28 L.
Explanation:
The given reaction equation is as follows.
This shows that 2 moles of gasoline requires 25 moles of . Hence, moles of oxygen required to react with 4 moles of gasoline are calculated as follows.
At STP, the pressure is 1 atm and temperature is 273.15 K. Therefore, using ideal gas equation the volume of oxygen is calculated.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
Thus, we can conclude that volume of oxygen at STP is needed for complete given combustion is 1121.28 L.
