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Dmitriy789 [7]
3 years ago
8

Rank these species by their ability to act as an oxidizing agent. cu+ mg2+ fe2+

Chemistry
1 answer:
natita [175]3 years ago
7 0

Explanation:

The species or elements which gain electrons and reduces itself are known as oxidizing agent or oxidant.

Ability of an element to act as an oxidizing agent depends on its electrode potential.

The electrode potential of Cu^{+} is 0.52 V.

The electrode potential of Fe^2+ is -0.41 V.

The electrode potential of Mg^{2+} is -2.38 V.

Greater is the value of electrode potential, stronger will be the oxidizing agent.

Therefore, rank of these species by their ability to act as an oxidizing agent are as follows.

       Cu^{+} > Fe^2+ > Mg^{2+}

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<h3>What is empirical formula?</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.

<h3>How to find the empirical formula?</h3>

Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.

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The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3

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