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3 years ago

Rank these species by their ability to act as an oxidizing agent. cu+ mg2+ fe2+

Chemistry

1 answer:

natita [175]3 years ago

7 0

Explanation:

The species or elements which gain electrons and reduces itself are known as oxidizing agent or oxidant.

Ability of an element to act as an oxidizing agent depends on its electrode potential.

The electrode potential of $Cu^{+}$ is 0.52 V.

The electrode potential of $Fe^2+$ is -0.41 V.

The electrode potential of $Mg^{2+}$ is -2.38 V.

Greater is the value of electrode potential, stronger will be the oxidizing agent.

Therefore, rank of these species by their ability to act as an oxidizing agent are as follows.

$Cu^{+}$ > $Fe^2+$ > $Mg^{2+}$

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2 years ago

He wants to increase the energy of emitted electrons . Based on the research of Albert Einstein, what is the best way for him to

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<h3>What is energy of emitted electron?</h3>

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<h3>Energy of the emitted electron</h3>

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2 years ago

CaC2 + 2H2O ➞ C2H2 + Ca(OH)2

Paraphin [41]

Answer:

A. 0.5 mole of Ca(OH)₂.

B. 4.37 moles of H₂O.

Explanation:

The balanced equation for the reaction is given below:

CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂

Next, we shall determine the mass of CaC₂ that reacted and the mass of C₂H₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of CaC₂ = 40 + (12×2)

= 40 + 24

= 64 g/mol

Mass of CaC₂ from the balanced equation = 1 × 64 = 64 g

Molar mass of C₂H₂ = (12×2) + (2×1)

= 24 + 2

= 26 g/mol

Mass of C₂H₂ from the balanced equation = 1 × 26 = 26 g

SUMMARY:

From the balanced equation above,

64 g of CaC₂ reacted with 2 moles of H₂O to produce 26 g of C₂H₂ and 1 mole of Ca(OH)₂.

A. Determination of the number of mole of Ca(OH)₂ produced by the reaction of 32.0 g of CaC₂.

From the balanced equation above,

64 g of CaC₂ reacted to produce 1 mole of Ca(OH)₂.

Therefore, 32 g of CaC₂ will react to produce = (32 × 1)/64 = 0.5 mole of Ca(OH)₂.

Thus, 0.5 mole of Ca(OH)₂ were obtained from the reaction.

B. Determination of the number of mole of H₂O needed to produce 56.8 g C₂H₂.

From the balanced equation above,

2 moles of H₂O reacted to produce 26 g of C₂H₂.

Therefore, Xmol of H₂O will react to produce 56.8 g C₂H₂ i.e

Xmol of H₂O = (2 × 56.8)/26

Xmol of H₂O = 4.37 moles

Thus, 4.37 moles of H₂O is needed for the reaction.

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