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Juli2301 [7.4K]

3 years ago

10

Which of the following takes place in the combustion chamber of a gas turbine engine?

1 answer:

antiseptic1488 [7]3 years ago

5 0

In the combustion chamber of a gas turbine engine the mixture of fuel oil and compressed air is ignited. The combustion chamber is responsible for supplying the energy which drives the system. For a turbine, the combustion chamber operates with periodical combustion and the space, where the combustion takes place is closed on the exhaust side leading to the actual turbine.

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A cyclist has a constant speed of 12 m/s. What is the magnitude of the displacement of the cyclist after 18 seconds?

Katyanochek1 [597]

Answer:

216 m

Explanation:

Assuming a straight line:

Δx = vt

Δx = (12 m/s) (18 s)

Δx = 216 m

7 0

3 years ago

_____ provides heat to flowing magma that forms convection cells.

Zina [86]

Answer:

C

Explanation:

Mantle convection is the very slow creeping motion of Earth's solid silicate mantle caused by convection currents carrying heat from the interior to the planet's surface. The Earth's surface lithosphere rides atop the asthenosphere and the two form the components of the upper mantle.

3 0

3 years ago

Read 2 more answers

A bicycle rider increases his speed from 5 m/s to 15 m/s in while accelerating at 2.5 m/s2. How long does this take ?

Olegator [25]

Answer:

4 seconds

Explanation:

Average acceleration is change in velocity over change in time:

a = Δv / Δt

Δt = Δv / a

Δt = (15 m/s - 5 m/s) / 2.5 m/s²

Δt = 4 s

3 0

4 years ago

Read 2 more answers

A striped billiard ball moves toward the right with speed 3 m/s. A solid billiard ball with the same mass moves toward the left

Helen [10]

Answer:

Final speed of striped ball is 3 m/s in left direction .

Explanation:

Given :

Two billiard ball with the same mass moves toward the left at the same speed 3 m/s .

Let , us assume right hand side direction to be positive and left hand side direction to be negative .

Also , let speed of ball after collision is (striped ball ) u and (solid ball) v .

It is also given that the collision is elastic .

Therefore , kinetic energy is conserved .

$\dfrac{m(3)^2}{2}+\dfrac{m(3)^2}{2}=\dfrac{mu^2}{2}+\dfrac{mv^2}{2}\\\\u^2+v^2=18$ ...... ( 1 )

Also , by conserving linear momentum .

We get :

$3m-3m=mu+mv\\u=-v$ ...... ( 2 )

Putting value of u from equation 2 to equation 1 .

We get :

$2v^2=18\\v=3\ m/s$

And , u = -3 m/s .

Therefore , final speed of striped ball is 3 m/s in left direction .

Hence , this is the required solution .

4 0

4 years ago

A charge of −8.3 μC is traveling at a speed of 7.4 × 106 m/s in a region of space where there is a magnetic field. The angle bet

solniwko [45]

Answer:

The magnitude of the magnetic field is $1.1\times 10^{-4}\, T$

Explanation:

Given charge q = −8.3 μC

speed of charge $v=7.4\times 10^{6}\, \frac{m}{s}$

Angle between magnetic field and the velocity of charge $\Theta =52^{\circ}$

Strength of magnetic force on charge $F=5.4\times 10^{6}\, N$

Let magnitude of magnetic field be B

Since the magnetic force on a free moving charge in the magnetic field given by

$F=\left |q\vec{v}\times \vec{B}\right |=\left | qvBsin\Theta\right |$

=> $5.4\times 10^{-3}=\left | -8.3\times 10^{-6}\times 7.4\times 10^{6}\times sin(52^{\circ})\times B \right |$

=> $B=1.1\times 10^{-4}\, T$

Thus the magnitude of the magnetic field is $1.1\times 10^{-4}\, T$

4 0

3 years ago