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3 years ago

As a solid reaches its melting point intermolecular bonds have been disrupted, causing:

Physics

2 answers:

pantera1 [17]3 years ago

6 0

Answer: Option (B) is the correct answer.

Explanation:

Melting point is defined as the point at which a solid substance changes into liquid state.

During the melting point temperature of substance remains constant until the whole solid substance changes into liquid state.

At the melting point, particles of the solid vibrate rapidly and as a result position of the particles changes from one place to another.

Thus, we can conclude that as a solid reaches its melting point intermolecular bonds have been disrupted, causing a change in particle position.

yarga [219]3 years ago

4 0

Answer:

Explanation: B. A change in particle position

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Answer:

2 m

Explanation:

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The ball would travel 3 m from the point of throwing then fall down 5 m to the ground. The total distance traveled is 7 m.

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3 years ago

An object is moving with the speed of light around the Earth. How much time will it take to complete one round trip along the eq

dimulka [17.4K]

Answer:

0.14 seconds

Explanation:

The speed of light in vacuum is approximately 3.0*10^8. The distance that would be covered by the object would be equivalent to the circumference of the cross-section of the earth on the equator.

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3 years ago

A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s west. Find the ve

Troyanec [42]

The velocity of tennis racket after collision is 14.96m/s

<u>Explanation:</u>

Given-

Mass, m = 0.311kg

u1 = 30.3m/s

m2 = 0.057kg

u2 = 19.2m/s

Since m2 is moving in opposite direction, u2 = -19.2m/s

Velocity of m1 after collision = ?

Let the velocity of m1 after collision be v

After collision the momentum is conserved.

Therefore,

m1u1 - m2u2 = m1v1 + m2v2

$v1 = (\frac{m1-m2}{m1+m2})u1 + (\frac{2m2}{m1+m2})u2$

$v1 = (\frac{0.311-0.057}{0.311+0.057})30.3 + (\frac{2 X 0.057}{0.311 + 0.057}) X-19.2\\\\v1 = (\frac{0.254}{0.368} )30.3 + (\frac{0.114}{0.368}) X -19.2\\ \\v1 = 20.91 - 5.95\\\\v1 = 14.96$

Therefore, the velocity of tennis racket after collision is 14.96m/s

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3 years ago