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3 years ago

21. Which of the equations is balanced?

1 answer:

7 0

The answer would be D
Because there are the same amount of elements on each side (3Mg on the left and 3 Mg on the right. Then 2 N on the left and 2 N on the right also)

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Describe a process in which energy changes forms at least twice

olga55 [171]

That would be like dropping your cell phone on to the ground by accident. The object (cell phone)'s gravitational potential energy would be converted to kinetic energy or energy in motion more precisely. This is just a hypothetical example though.

7 0

3 years ago

A student uses 150 N to push a block of wood up a ramp at constant velocity of 2.6m/s. What is his power output?

11Alexandr11 [23.1K]

Answer:

P= 390 W

Explanation:

In physics, power is the rate of doing work or of transferring heat, i.e. the amount of energy transferred or converted per unit time. Work is a force F applied over a distance x. Matemathicaly it means

P = dW/dt ≈ d(F * x)/dt = xdF/dt + Fdx/dt. If force is constant dF/dt=0 so P=F dx/dt = P*v, where v is velocity, the rate of distance per unit time.

We have force and velocity. Newton is unit of Kg*m/s2, hence

P= 150 kgm/s2 * 2.6 m/s =390 Kgm2/s3 = 390 W, where W is Watts and is an unit of power

8 0

3 years ago

ly charged particles are held 24 x 103m apart and then released from rest. The initial acceleration of the first particle is obs

inessss [21]

Answer:

Part a)

$m_2 = 4.9 \times 10^7 kg$

Part b)

$q_1 = q_2 = 5312.6 C$

Explanation:

Part a)

As we know that both charge particles will exert equal and opposite force on each other

so here the force on both the charges will be equal in magnitude

so we will have

$F = m_1a_1 = m_2a_2$

here we have

$6.3 \times 10^7(7) = m_2(9)$

now we have

$m_2 = 4.9 \times 10^7 kg$

Part b)

Now for the force between two charges we can say

$F = \frac{kq_1q_2}{r^2}$

now we have

$(6.3 \times 10^7)(7) = \frac{(9\times 10^9)q^2}{(24\times 10^3)^2}$

now we have

$q_1 = q_2 = 5312.6 C$

3 0

3 years ago

A person hears the echo of his own sound from a distance hill after 2 seconds . How far is the person from the hill , if the spe

Scorpion4ik [409]

Answer:

the distance between the person and the hill is 330 m.

Explanation:

Given;

speed of sound in air, v = 330m/s

time of sound travel, t = 2 s

The distance between the person and the hill is calculated as;

$Distance = Speed \ \times \ Time\\\\Time \ of \ echo = \frac{2\ \times \ distance}{speed} \\\\distance = \frac{Time \ of \ echo \ \times \ speed}{2} \\\\distance = \frac{2 \ \times \ 330}{2} \\\\distance = 330 \ m$

Therefore, the distance between the person and the hill is 330 m.

3 0

3 years ago

HELP ASAP! PLEASEEEE <br><br>

Lady_Fox [76]

Explanation:

Sorry i had to post it here. This is for the chemistry question on The top

5 0

3 years ago