Ball will hit the ground after a time of 1.296 s
Explanation:
initial velocity of ball= Vi=0
g= 9.8 m/s²
height =h= 27 ft=8.23 m
using the kinematic equation
h= Vi t + 1/2 gt²
8.23=0(t) + 1/2 (9.8)t²
t²=1.6796
t=1.296 s
Answer:
1.33
Explanation:
speed of light in vacuum, c = 3 x 10^8 m/s
speed of light in medium, v = 2.26 x 10^8 m/s
The refractive index of the medium is given by
μ = speed of light in vacuum / speed of light in medium
μ = (3 x 10^8) / (2.26 x 10^8)
μ = 1.33
Solution:
The world record for the longest flight by a human cannonball is approximately 200 feet and therefore the human cannon catapult that Bobo would need is one that would be able to propel him with an initial velocity of more than 120 kilometer per hour (more than the speed of the current record holder) with the cannon directed at an angle 45 degrees above the horizonal
Learn more about the projectile motion here:
brainly.com/question/24240176
Answer:
Explanation:
Angular velocity ω = 2π / T = 2 x 3 . 14 / (4 x 60 ) = .026 rad / s.
d = D Sin ( ωt + θ ) where D = amplitude = 11 m θ = initial phase.
-11 = 11 sin ( 0 + θ ) = sin θ = -1 , θ = - π /2
So, d = D Sin ( ωt - θ )
d = 11 Sin ( .026 t - π /2 ) is the required equation.
