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yaroslaw [1]
2 years ago
14

Which of the following can cause a flopping sound at the front of the engine

Engineering
1 answer:
Irina-Kira [14]2 years ago
3 0
B) timing chain too loose
You might be interested in
Refrigerant 134a enters the evaporator of a refrigeration system operating at steady state at -16oC and a quality of 20% at a ve
Dmitry [639]

Answer:

mass flow rate = 0.0534 kg/sec

velocity at exit = 29.34 m/sec

Explanation:

From the information given:

Inlet:

Temperature T_1 = -16^0\ C

Quality x_1 = 0.2

Outlet:

Temperature T_2 = -16^0 C

Quality  x_2 = 1

The following data were obtained at saturation properties of R134a at the temperature of -16° C

v_f= 0.7428 \times 10^{-3} \ m^3/kg \\ \\  v_g = 0.1247 \ m^3 /kg

v_1 = v_f + x_1 ( vg - ( v_f)) \\ \\ v_1 = 0.7428 \times 10^{-3} + 0.2 (0.1247 -(0.7428 \times 10^{-3})) \\ \\  v_1 = 0.0255 \ m^3/kg \\ \\ \\  v_2 = v_g = 0.1247 \ m^3/kg

m = \rho_1A_1v_1 = \rho_2A_2v_2 \\ \\  m = \dfrac{1}{0.0255} \times \dfrac{\pi}{4}\times (1.7 \times 10^{-2})^2\times 6  \\ \\ \mathbf{m = 0.0534 \ kg/sec}

\rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ A_1 =A_2  \\ \\  \rho_1v_1 = \rho_2v_2   \\ \\ \implies \dfrac{1}{0.0255} \times6 = \dfrac{1}{0.1247}\times (v_2)\\ \\ \\\mathbf{\\ v_2 = 29.34 \ m/sec}

3 0
2 years ago
Five batch jobs A through E arrive at a computer center in the order A to E at almost the same time. They have estimated running
Nikolay [14]

Answer:

Explanation:

The Turnaround time is the amount of time that elapses between the job arriving and completing. We assume that all jobs arrive at time 0, the turnaround time will simply be the time that they complete.

Round Robin:

we assume that the time quantum of the scheduler is 1 second.The table below gives a break down of which jobs will be processed during each time quantum. A asterisk(*) indicates that the job completes during that quantum.

1   2   3   4   5   6   7   8   9   10   11   12   13   14   15   16   17   18   19   20   21   22   23   24   25   26   27   28   29    30

A  B  C   D  E  A  B   C* D  E    A    B    D   E    A   B   D*   E     A   B     E     A    B* E   A     E  A    E*  A A

C* = 8

D*=17

B*=23

E*=28

AVERAGE TURNAROUND = (8+17+23+28+30)/5 =106/5 = 21.2 MINUTES

B) PRIORITY SCHEDULING:

1-6       7-14        15-24      25-26        27-30

   

 B           E             A             C            D

     AVERAGETURNAROUND =(6+14+24+26+30)/5 = 100/5 = 20 MINUTES.

C)FCFS

1-10      11-16      17-18      19-22      23-30

 

   A            B              C            D              E

   

AVERAGE TURNAROUND =(10+16+18+22+30)/5 = 96/5=19.2 MINTUES

D)SJF

1-2        3-6         7-12         13-20      21-30

C           D            B               E                A

AVERAGE TURNAROUND - (2+6+12+20+30)/5 =70/5 =14 MINUTES.

3 0
2 years ago
Calculate the unit cell edge length for an 80 wt% Ag−20 wt% Pd alloy. All of the palladium is in solid solution, the crystal str
alisha [4.7K]

Answer:

λ^3 = 4.37

Explanation:

first let us to calculate the average density of the alloy

for simplicity of calculation assume a 100g alloy

80g --> Ag

20g --> Pd

ρ_avg= 100/(20/ρ_Pd+80/ρ_avg)

         = 100*10^-3/(20/11.9*10^6+80/10.44*10^6)

         = 10744.62 kg/m^3

now Ag forms FCC and Pd is the impurity in one unit cell there is 4 atoms of Ag since Pd is the impurity we can not how many atom of Pd in one unit cell let us calculate

total no of unit cell in 100g of allow = 80 g/4*107.87*1.66*10^-27

                                                          = 1.12*10^23 unit cells

mass of Pd in 1 unit cell = 20/1.12*10^23

Now,

                      ρ_avg= mass of unit cell/volume of unit cell

                      ρ_avg= (4*107.87*1.66*10^-27+20/1.12*10^23)/λ^3

                          λ^3 = 4.37

6 0
3 years ago
Code scramble: make the program sort the three numbers x, y and z into increasing order, so that x has the smallest value, y has
riadik2000 [5.3K]

Answer:

This question is taken from code scramble exercise which has scattered lines which are to be arranged by dragging and dropping with mouse to  to get the desired output in which x has the smallest value, y has the next smallest value, and z has the largest value. So the correct arrangement is as following:

tmp=max(x,y)  

x=min(x,y)  

y=tmp  

tmp=max(y,z)  

y=min(y,z)

z=tmp  

tmp=max(x,y)  

x=min(x,y)  

y=tmp

Explanation:

So the flow works as following:

First the maximum of x and y is taken and the result is stored in a temporary variable tmp which is used so that the original values do not get affected or modified by the operations performed by the functions. Lets say that x=30 y=15 and z=40

Now the max() functions returns the maximum from the values of x and y. As x=30 and y=15 so value of x is stored in tmp which is 30 as 30>15

Next the min() function finds the minimum from the values of x and y and stores the result in x. As the minimum value is 15 so this value is stored in x and now x=15

y = tmp means now the value in tmp is copied to y, So y = 30

Next the max() function finds the maximum value from the values of y and z. As y=30 and z=40 So the maximum value is 40 so tmp variable now contains the value 40.

Next the min() function finds the minimum from the values of y and z and stores the result in y. As the minimum value is 30 so this value is stored in y which means y remains 30 so, y=30

z = tmp means now the value in tmp is copied to z, So z= 40

Now the max() functions returns the maximum from the values of x and y. After the operations of above functions the new value of x and y are: x=15 and y=30 so value of y is stored in tmp which is 30 as 30>15

Next the min() function finds the minimum from the values of x and y and stores the result in x. As the minimum value is 15 so this value is stored in x and x remains: x=15

y = tmp means now the value in tmp is copied to y, So y remains: y = 30

So the final values of x, y and z are:

x = 15 y = 30 z = 40

If you want to make a program which sort the values in x, y and z then i am providing a simple Python program that serves the purpose:

x = int(input("enter first number: "))

y = int(input("enter second number: "))

z = int(input("enter third number: "))

a1 = min(x, y, z)

a3 = max(x, y, z)

a2 = (x + y + z) - a1 - a3

print("x =",a1,"y=",a2,"z=",a3)

The program asks user to enter the value for x, y and z.

Then the minimum value from the values of x,y and z is computed using min() function and the result is stored in a1. This will be the value of x. Then the maximum value from value of x,y and z is computed using max() function and the result is stored in a2. This will be the value of z. Next the statement: a2 = (x + y + z) - a1 - a3  works as following:

Lets say the values of x = 30 y = 15 and z = 40 So a1 = 15 and a2 = 40

a2 = 30 + 15 + 40 - 15 - 40

a2 = 30

This is the value of y

So  print("x = ",a1,"y = ",a2,"z = ",a3) displays the following output:

x = 15 y = 30 z = 40

3 0
3 years ago
You receive the bill for servicing your diesel engined car. As a good engineer you immediately notice that one of the items on b
vichka [17]

Answer:

b. spark plugs

Explanation:

Diesel engines are characterized in that the mechanism that activates the explosion of fuel is high pressures, so when the piston reaches the top of the cylinder, the pressure of the air-diessel mixture is so high that it causes the explosion, this It is what generates the power in a diesel engine.

3 0
2 years ago
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