All categories

2 years ago

What is the value of x in the equation 3 minus 2 x = negative 1.5 x? –6 –2 2 6

Mathematics

2 answers:

olga_2 [115]2 years ago

4 0

Answer:

x=118.25

Step-by-step explanation:

3−2x=−1.5−6−226

3+−2x=−1.5+−6+−226

−2x+3=(−1.5+−6+−226)(Combine Like Terms)

−2x+3=−233.5

Step 2: Subtract 3 from both sides.

−2x+3−3=−233.5−3

−2x=−236.5

Step 3: Divide both sides by -2.

−2x

−2

−236.5

−2

x=118.25

Paladinen [302]2 years ago

3 0

Answer:x=67.142857

Step 1: Simplify both sides of the equation.

3−2x−1.5x=−6−226

3+−2x+−1.5x=−6+−226

(−2x+−1.5x)+(3)=(−6+−226)(Combine Like Terms)

−3.5x+3=−232

Step 2: Subtract 3 from both sides.

−3.5x+3−3=−232−3

−3.5x=−235

Step 3: Divide both sides by -3.5.

−3.5x

−3.5

−235

−3.5

x=67.142857

Answer:

x=67.142857

Step-by-step explanation:

You might be interested in

Help again. I’m really bad at this.

siniylev [52]

Given the equation of a circle in the form

$(x-x_0)^2+(y-y_0)^2=r^2$

You have that $(x_0,y_0)$ is the center, and $r$ is the radius.

So, in your case, the center is $(-9,6)$ and the radius is 5.

6 0

2 years ago

If a car is traveling at 70 mph, how fast is the car traveling in feet per second? Round to 2 decimal places. (Reminder: there a

alukav5142 [94]

Answer:

264000

Step-by-step explanation:

5 0

3 years ago

The volume of a shampoo filled into a container is uniformly distributed between 370 and 385 milliliters. (a) What are the mean

Olenka [21]

Answer:

(a) mean = 377.5ml. standard deviation = 4.33

(b) 0.333

Step-by-step explanation:

(a)The mean:

$\mu = \frac{385 + 370}{2} = 377.5 ml$

The standard deviation:

$\sigma = \frac{385 - 370}{\sqrt{12}} = 4.33$

(b)

$P(x < 375) = \frac{375 - 370}{385 - 370} = \frac{1}{3} \approx 0.333$

(c)P(x > m) = 0.95

$\frac{m - 370}{385 - 370} = 0.95$

$m - 370 = 14.25$

$m = 384.25ml$

So the volumn of shampoo should be 384.25ml to exceed 95% of containers.

7 0

2 years ago

Find the domain and range of the function:<br> f(x) =5-x-3 to the square root<br> Domain:<br> Range:

mario62 [17]

Domain: ( -infinity, infinity ) , { x|x € R }
Range: ( -infinity, infinity ) , { y|y € R }

6 0

2 years ago

Read 2 more answers

1. (a) Use the integral test to show that P[infinity] n=1 1/n4 converges. (b) Find the 10th partial sum, s10, of the series P[in

scZoUnD [109]

Answer:

Step-by-step explanation:

a) $\int\limits^{\infty} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}$

Substitute limits to get

= $\frac{1}{3}$

Thus converges.

b) 10th partial sum =

$\int\limits^{10} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}$

= $\frac{-1}{3} (0.001-1)\\= 0.333$

c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)

where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .

(question is not clear)

3 0

2 years ago