For astronomical objects, the time period can be calculated using:
T² = (4π²a³)/GM
where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)
Thus,
T² = a³
a = ∛(29.46²)
a = 0.67 AU
1 AU = 1.496 × 10⁸ Km
0.67 * 1.496 × 10⁸ Km
= 1.43 × 10⁹ Km
Answer:
B = 0.15 T
Explanation:
To find the magnitude of the magnetic field you use the following formula:
( 1 )
m: mass of the electron = 9.1*10^-31 kg
v: velocity of the electron = 3*10^6 m/s
q: charge = 1.6*10^-19
r: radius = 0.11mm = 0.11*10^-3 m
You replace the values of the parameters in the equation (1).

the magnetic field has a magnitude of 0.15 T
Answer:
With all of that information, he's telling us the train's VELOCITY.
Explanation:
Velocity is a vector quantity made of two parts: speed and direction.