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bearhunter [10]
3 years ago
7

. Suppose you walk 18.0 m straight west and then 25.0 m straight north. How far are you from your starting point? What is your d

isplacement vector? What is the direction of your displacement? Assume the +x-axis is to the east.
Physics
1 answer:
Scorpion4ik [409]3 years ago
5 0

Answer:

Explanation:

The total distance is how far you walk from the starting point.

Distance through west = 18.0m

Distance through north = 25.0m

Total distance covered = 18.0+25.0m

Total distance covered = 43.0m

This means that I am 43.0m from the starting point

Displacement is the distance covered in a specified direction. The displacement will be gotten using the Pythagoras theorem as shown:

d^2 = 25^2 + 18^2\\d^2 = 625+324\\d^2 = 949\\d = \sqrt{949}\\ d = 30.81m

The direction of your displacement is 30.81m

Direction is gotten according to the formula;

\theta = tan ^{-1}{\frac{y}{x} }\\\theta = tan ^{-1}{\frac{25}{-18} }\\\theta = tan ^{-1}-1.3889}\\\theta = -60.27^0\\\theta = 180-60.27\\\theta = 119.7^0

<em>Note that the direction to the west is negative, that is why the x is -18.0m</em>

<em></em>

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<u>Charge</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>particle</u><u> </u><u>is</u><u> </u><u>1</u><u> </u><u>coulomb</u><u>.</u>

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