Answer: In this lab we wanted to know how motion can be described. So the hypothesis is if the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car will have a greater acceleration. My prediction is that cars travel faster on higher tracts. So the heighten the track was intentionally manipulated. So it is the independent variable the speed of the car is the dependent variable. The speed at the first quarter checkpoint is 1.09 m/s. The speed at the second quarter checkpoint is 1.95 m/s. The speed at the third quarter checkpoint is 2.373.36 m/s. The speed at the finish line is 2.803.00 m/s. The average speed increases as the height increases.
The cars on the higher track travel farther than the cars on the lower track, in the same time.
This means that the cars on the higher track have a greater average speed than those on the lower track. This is demonstrated by the
slope of the higher track line being greater than the slope of the lower track line.
Explanation: put it in notes then send it to files to compress it to submit it.
Answer:
<u>Charge</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>particle</u><u> </u><u>is</u><u> </u><u>1</u><u> </u><u>coulomb</u><u>.</u>
Explanation:
Force, F:

F is magnetic force.
B is the magnetic flux density.
e is the charge of the particle.
V is the velocity

Answer:
281 K
Explanation:
Charles's Law. V1/T1 = V2/T2.
The temperature must be in K = 21.6°C + 273 = 294.6K.
V1T2 = V2T1.
3.62L x T2 = 3.45L x 294.6K
T2 = (3.45 x 294.6) / 3.62 = 1016.4 / 3.62 = B): 281K.
(By direct proportion of volume change: (3.45L / 3.62L) x 294.6K = 281K).
If the ladder is vertical, then the work done in ascending equals his increase in potential energy.
For a man of mass (m) climbing height (h), the PE is (mgh), where g is the acceleration due to gravity.
If he does this in time t, his average power (rate of working) is:
mgh / t
= 80 * 9.81 * 6 / 12
= 392.4 W.
If the ladder is not vertical but inclined at an angle the horizontal, the power is mgh sin(a) / t.