The distance for any rectilinear motion at constant acceleration is:
d = v₀t + 0.5at²
where
v₀ is the initial velocity
So, if v₀ = 6v, and it stopped to 0 m/s, then the acceleration is equal to:
a = (0 - 6v)/t = -6v/t
Thus,
d = (6v)(t) + (0.5)(-6v/t)(t²)
d = 6vt - 3t
<span>d = 3t(2v - 1)</span>
Answer:
-0.1875 V.
Explanation:
Using
E₂ = MdI₁/dt........................ Equation 1
Where E₂ = Voltage induced in the second coil, M = mutual inductance of both coil, dI₁ = change in current in the first coil, dt = change in time.
Given: M = 3.00 mH = 0.003 H, dI₁ = (0-2.50) = -2.5 A, dt = 40 ms = 0.04 s.
Substitute into equation 1
E₂ = 0.003(-2.5)/0.04
E₂ = -0.1875 V.
Hence the induced emf = -0.1875 V.
Answer:
Total momentum, p = 55 kg-m/s
It is given that,
Mass of player 1, m₁ = 85 kg
Mass of player 2, m₂ = 105 kg
Speed of player 1, v₁ = -8 m/s (west)
Speed of player 2, v₂ = 7 m/s (east)
Momentum is equal to the product of mass and velocity. For this system, momentum is given by :
p=m_1v_1+m_2v_2p=m
1
v
1
+m
2
v
2
p=85\ kg\times (-8\ m/s)+105\ kg\times 7\ m/sp=85 kg×(−8 m/s)+105 kg×7 m/s
p = 55 kg-m/s
The total momentum of the system made up of the two players is 55 kg-m/s.
A). balanced force
b). unbalanced force
There's no such thing as either of these. A group of two or more forces can be balanced or unbalanced. A single force can't be.
c). gravitational force ... doesn't cause an object to move in a circle;
Drop a stone from the roof of a tall building and watch it fall.
It goes straight down, not in a circle.
d). centripetal force ... force directed toward the center of a circle,
causes an object to move in a circle.
