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Aleks04 [339]
3 years ago
11

Technician A says that the neutral safety switch must be bad and should be replaced. Technician B says that the neutral safety s

witch could require adjustment. Who is correct ?
Engineering
2 answers:
lukranit [14]3 years ago
3 0

Answer:

Technician A is correct

Explanation:

The neutral safety switch when bad must be replaced and not adjusted as suggested by technician B because if the neutral safety switch is bad the Engine might not crank when put in neutral but it will crank when put in park and this is very bad for the life of the Engine it is better to replace it. A test for a bad/faulty neutral safety switch will be required to ascertain the level of damage it might cause to the Engine and prompt replacement is essential as well.  because the neutral helps to prevent the car from starting when it is already engaged in a gear position therefore protecting the car from sudden collisions

Greeley [361]3 years ago
3 0

Answer:Technician A is correct

Explanation:

Considering the potential damages that could arise from a bad neutral safety , it is a good preventive measure to change such device other than trying to make adjustment on it . As the adjusted switch could return to it faulty place again so a complete replacement is a better option.

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Explanation:

the total resistance is equal to the total potential difference divided by the Current

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Given the following MATLAB statement: ( 3 + 2 ) / 5 * 4 + 5 ^ 2 In what order will these operations be done?
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first is the parentheses, (3+2)=5 next is the exponent 5^2=25, next is the division 5 / 5 = 1, then the multiplication 4*1=4 and then you add 4+25=29. so the answer is 29.

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Which type of modeling can create virtual designs that can save clients thousands of dollars?
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VR Prototyping

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3 years ago
Working with which of these systems requires a technician that has been certified in an EPA-approved course?
makvit [3.9K]

EPA Regulations provides a certified course for the technicians involved in the Air-conditioning system.

Answer: Option (b)

<u>Explanation:</u>

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6 0
3 years ago
A four-cylinder, four-stroke internal combustion engine has a bore of 3.7 in. and a stroke of 3.4 in. The clearance volume is 16
abruzzese [7]

Answer:

1) The three possible assumptions are

a) All processes are reversible internally

b) Air, which is the working fluid circulates continuously in a closed loop

cycle

c) The process of combustion is depicted as a heat addition process

2) The diagrams are attached

5) The net work per cycle is 845.88 kJ/kg

The power developed in horsepower ≈ 45374 hP

Explanation:

1) The three possible assumptions are

a) All processes are reversible internally

b) Air, which is the working fluid circulates continuously in a closed loop

cycle

c) The process of combustion is depicted as a heat addition process

2) The diagrams are attached

5) The dimension of the cylinder bore diameter = 3.7 in. = 0.09398 m

Stroke length = 3.4 in. = 0.08636 m.

The volume of the cylinder v₁= 0.08636 ×(0.09398²)/4 = 5.99×10⁻⁴ m³

The clearance volume = 16% of cylinder volume = 0.16×5.99×10⁻⁴ m³

The clearance volume, v₂  = 9.59 × 10⁻⁵ m³

p₁ = 14.5 lbf/in.² = 99973.981 Pa

T₁ = 60 F = 288.706 K

\dfrac{T_{2}}{T_{1}} = \left (\dfrac{v_{1}}{v_{2}}  \right )^{K-1}

Otto cycle T-S diagram

T₂ = 288.706*6.25^{0.393} = 592.984 K

The maximum temperature = T₃ = 5200 R = 2888.89 K

\dfrac{T_{3}}{T_{4}} = \left (\dfrac{v_{4}}{v_{3}}  \right )^{K-1}

T₄ = 2888.89 / 6.25^{0.393} = 1406.5 K

Work done, W = c_v×(T₃ - T₂) - c_v×(T₄ - T₁)

0.718×(2888.89  - 592.984) - 0.718×(1406.5 - 288.706) = 845.88 kJ/kg

The power developed in an Otto cycle = W×Cycle per second

= 845.88 × 2400 / 60  = 33,835.377 kW = 45373.99 ≈ 45374 hP.

8 0
3 years ago
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