Answer:
Electroosmotic velocity will be equal to 
Explanation:
We have given applied voltage v = 100 volt
Length of capillary L = 5 mm = 0.005 m
Zeta potential of the capillary surface 
Dielectric constant of glass is between 5 to 10 here we are taking dielectric constant as 
Viscosity of glass is 
Electroosmotic velocity is given as 

So Electroosmotic velocity will be equal to 
Answer:
minimum electric power consumption of the fan motor is 0.1437 Btu/s
Explanation:
given data
area = 3 ft by 3 ft
air density = 0.075 lbm/ft³
to find out
minimum electric power consumption of the fan motor
solution
we know that energy balance equation that is express as
E in - E out =
......................1
and at steady state
= 0
so we can say from equation 1
E in = E out
so
minimum power required is
E in = W = m
=
put here value
E in =
E in =
E in = 0.1437 Btu/s
minimum electric power consumption of the fan motor is 0.1437 Btu/s
AnswerWhat Are the Classifications of Burns? Burns are classified as first-, second-, or third-degree, depending on how deep and severe they penetrate the skin's surface. First-degree burns affect only the epidermis, or outer layer of skin. The burn site is red, painful, dry, and with no blisters.
Explanation:
Answer:
maximum stress is 2872.28 MPa
Explanation:
given data
radius of curvature = 3 ×
mm
crack length = 5.5 ×
mm
tensile stress = 150 MPa
to find out
maximum stress
solution
we know that maximum stress formula that is express as
......................1
here σo is applied stress and a is half of internal crack and t is radius of curvature of tip of internal crack
so put here all value in equation 1 we get
σm = 2872.28 MPa
so maximum stress is 2872.28 MPa
Answer:
40 ft
Explanation:
Assuming no loss of energy in the system of pulleys, the work done is the same whether you move the load directly or through the pulleys.
W = Fd . . . . . . . . work is the product of force and distance
F(10 ft) = (0.25F)(d) . . . . . where d is the distance we want to find
d = 10F/(0.25F) = 40
The rope will need to move 40 feet.