The same amount of energy is released when they recombine.
<h3>How to separate oxygen and hydrogen from water?</h3>
- Electrolysis is a promising choice for without carbon hydrogen creation from inexhaustible and atomic assets.
- Electrolysis is the method involved with utilizing power to part water into hydrogen and oxygen.
- This response happens in a unit called an electrolyzer.
- Electrolyzers can go in size from little, apparatus size hardware that is appropriate for limited scope dispersed hydrogen creation to huge scope, focal creation offices that could be tied straightforwardly to sustainable or other non-ozone depleting substance radiating types of power creation.
<h3>How Does it Work?</h3>
Like energy components, electrolyzers comprise of an anode and a cathode isolated by an electrolyte. Different electrolyzers capability in various ways, fundamentally because of the different kind of electrolyte material included and the ionic species it conducts.
To learn more about electrolysis from the given link
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Answer:
KCl
Explanation:
Look at the electronegativity differences between the pairs of elements:
KCl: 3.16 - 0.82 = 2.34
BeCl: 3.16 - 1.57 = 1.59
LiCl: 3.16 - 0.98 = 2.18
ClO: 3.44 - 3.16 = 0.28
KCl has the highest electronegativity difference; thus it is the most ionic bond of the 4.
<h3>
Answer:</h3>
B Aqueous
<h3>
Explanation:</h3>
We are given the equation;
KBr (aq) + AgNO₃ (aq) → KNO₃ (aq) + AgBr (s)
- The equation shows a precipitation reaction or a double displacement reaction.
- Precipitation reaction because two soluble salts reacts to produce a precipitate as one of the product.
- Double displacement reaction because the salts exchange cations and anions to form new compounds
- In the equation;
- KBr is in aqueous state since all salts of potassium (K) are soluble in water.
- KNO₃ and AgNO₃ are also in aqueous state as all nitrates are soluble in water.
- AgBr on the other hand is in solid state since its a precipitate that is insoluble in water.
Explanation:
The first wave was found to have a wavelength of 3 x 10⁵ m and the second wave had a wavelength of 3 x 10⁴ m
We need to find which wave have a higher frequency.
The relation between frequency and wavelength is given by :
Let f₁ and f₂ be the frequency of wave 1 and wave 2.
And
Hence, the wave having less wavelength will have higher frequency. The wave having wavelength 3 x 10⁴ m will have higher frequency.
