All categories

3 years ago

In the woman's mouth if

Physics

1 answer:

Tpy6a [65]3 years ago

7 0

Answer:

hi mate,

interesting question, first of all the pressure is determined by using the following formula:

Pg = p * G * h

where p is the density of the liquid, G is the gravity and h is the height difference, in you case you have:

p = 1015 kg/m3

G = 9.8m/s2

h = 0.085 m

insert these values into the equation above:

Pg = 1015 kg/m3 * 9.8m/s2 * 0.085 m = 849.81 kg·m-1·s-2 or 849.81 pascal

hope it helps, :-)

please mark me as brainliest

You might be interested in

An object’s average density rho is defined as the ratio of its mass to its volume: rho=M/V. The earth’s mass is 5.94×1024kg, and

ladessa [460]

Answer:

The answer to your question is 5.5 x 10¹² kg/km³

Explanation:

Data

density = rho = X

mass = 5.94 x 10²⁴ kg

volume = 1.08 x 10¹² km³

Process

To solve this problem use the density formula and simplify it to find the result.

Formula

density = $\frac{mass}{volume}$

Substitution

density = $\frac{5.94 x 10^{24} }{1.08 x 10^{12}}$

Simplification and result

density = 5.5 x 10¹² kg/km³

5 0

3 years ago

Why are cockpits not pressurized

Darina [25.2K]

It be more productive to just have the pilot were an oxygen mask instead of using the entire section for air when the pilot is siting down. The glass may also fog up, causing the entire glass pane to explode at high altitude.

5 0

3 years ago

17. A skateboard has a mass of 3.2 kg. If it slips out from a skateboarder and has

Akimi4 [234]

<h2>Book will hit the foot with force 21.8 N</h2>

Explanation:

The momentum of any object = m v

here m is the mass of body and v is its velocity

Thus momentum P = 3.2 x 1 = 3.2 kg-m

As the book is falling freely , so it will fall with and acceleration g

The force exerted by it is = m g

Thus force = 2.18 x 10 = 21.8 N

6 0

3 years ago

The critical angle for total internal reflection occurs when:___________.

Anastaziya [24]

Answer:

b) the refracted ray has an angle of 90 degrees

Explanation:

The angle of incidence is measured with respect to the normal separation of the media. The critical angle for total internal reflection occurs is:

$\theta=arcsin(\frac{n_2}{n_1})$

Here $n_2$ and $n_1$ are the refractive index of the mediums. This equation is an application of Snell's law, for the case where the refracted ray has an angle of $90^\circ$ .

5 0

3 years ago

From the edge of a cliff, a 0.41 kg projectile is launched with an initial kinetic energy of 1430 J. The projectile's maximum up

NemiM [27]

Answer:

v₀ₓ = 63.5 m/s

v₀y = 54.2 m/s

Explanation:

First we find the net launch velocity of projectile. For that purpose, we use the formula of kinetic energy:

K.E = (0.5)(mv₀²)

where,

K.E = initial kinetic energy of projectile = 1430 J

m = mass of projectile = 0.41 kg

v₀ = launch velocity of projectile = ?

Therefore,

1430 J = (0.5)(0.41)v₀²

v₀ = √(6975.6 m²/s²)

v₀ = 83.5 m/s

Now, we find the launching angle, by using formula for maximum height of projectile:

h = v₀² Sin²θ/2g

where,

h = height of projectile = 150 m

g = 9.8 m/s²

θ = launch angle

Therefore,

150 m = (83.5 m/s)²Sin²θ/(2)(9.8 m/s²)

Sin θ = √(0.4216)

θ = Sin⁻¹ (0.6493)

θ = 40.5°

Now, we find the components of launch velocity:

x- component = v₀ₓ = v₀Cosθ = (83.5 m/s) Cos(40.5°)

<u>v₀ₓ = 63.5 m/s</u>

y- component = v₀y = v₀Sinθ = (83.5 m/s) Sin(40.5°)

7 0

3 years ago