A 3.50-meter length of wire with a crosssectional

1 answer:

6 0

Resistance = (voltage) / (current)

(1.5 V) / (24 A) = 0.0625 ohm.

All that business about the description of the conductor ...
its length, size, temperature, color, price, etc. ... is only
there to distract and confuse us. It's all irrelevant.

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The illuminance On a surface is six lux and the surface is 4 meters from the light source what is the intensity of the source

Liula [17]

Answer : 96 candelas

Explanation : Luminous intensity is a quantity of light that is emitted by a light source with a solid angle in a particular direction.

We know the formula of luminous intensity

Luminous intensity = illuminance x distance from light source

$L_{v} = E_{v}\times d^{2}$

$L_{v} = 6\times 16\ candelas$

$L_{v} = 96\ candelas$

So, the intensity of the source will be 96 candelas.

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3 years ago

A professor sits on a rotating stool that is spinning at 10.0 rpm while she holds a heavy weight in each of her hands. Her outst

USPshnik [31]

Answer:

0.3950m

Explanation:

Use conservation of angular momentum:

Let L be the angular momentum(a vector).

We know that: $p=mv, L=l\omega, \ \ \ l=\sum (m_ir_i^2)}$ and that the two masses have the same radius:

$L_o=2mr_o^2\omega_o=L_f=2mr_f^2\omega_f\\\\r_o=0.795m,\omega_o=10\times2\pi \ rad/m , \omega_f=40.5\times 2\pi \ rad/m\\\\\therefore r_f=r_o\sqrt{(w_o/w_f)}\\\\r_f=0.795\sqrt{(10.0/40.5)}\\\\r_f=0.3950m$

Hence, the weights are 0.3950m away .

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3 years ago

As an tempature decreases what happens to the rate of radiation?

Firlakuza [10]

As the temperature decreases, the rate of radiation goes down, but the radiation exists as long as the temperature is above the absolute zero, which is actually 0 Kelvin. 0 Kelvin equals -273°C or -460°F. All objects in the world radiate if above that temperature.

5 0

3 years ago

What vertical distance Δy does a free-falling particle travel from the moment it starts to the moment it reaches a speed of 7.9

mr_godi [17]

Answer:

3.2 m

Explanation:

The equation to use to solve this problem is:

$v_f^2 = v_i^2 + 2 a \Delta y$