To find the relative frequencies, divide each frequency by the total number of throws - in this case, 100.
Red: 10/100=1/10=0.1
Yellow:35/100=0.35
Blue:48/100= 0.48
Misses: 7/100=0.07
The event of landing in the red region has a relative frequency of 0.1 which means the dart landed in the red region about 10% (0.1 x 100%) of the time.
Answer:
a. Exactly the same as the magnitude of the charge of the proton.
Explanation:
The elementary charge (e) is the smallest electric charge that can exist in the universe. Any positive or negative electric charge can be expressed as a multiple of the elementary charge, since is the electric charge carried by a single proton or, equivalently, the magnitude of the electric charge carried by a single electron (-1e).

9. An object which is in circular motion (moving along a circle) is said to be accelerating because it changes it's direction constantly even if it is moving with a constant speed. cuz acceleration is change in either magnitude or direction of an object with respect to time.
therefore, it's still acceleration as change in direction with time.
10. Average speed of an object can be calculated by dividing the total distance covered by an object by time taken to cover that distance.
i.e
it can be re- arranged to find the distance as :
11. speed = 20 m/s : conversion into km/h
distance covered : 4 km = 4000 m
time taken = 200 seconds
12. let's use the first equation of motion to find the acceleration :
Answer:
The new current in the straight wire is 4.98 A
Explanation:
Given;
initial magnetic force on the wire, F₁ = 0.017 N
initial current flowing on the straight wire, I₁ = 1.1 A
When the current in the wire is changed,
new magnetic force on the wire, F₂ = 0.077 N
the new current in the wire, I₂ = ?
Applying equation of magnetic force on conductor;
F₁ = I₁BLsinθ
F₂ = I₂BLsinθ
BLsinθ = F₁/I₁ = F₂/I₂
I₂ = (F₂I₁)/F₁
I₂ = (0.077 x 1.1) / 0.017
I₂ = 4.98 A
Therefore, the new current in the straight wire is 4.98 A