Question

Two blocks A and B with mA = 2.6 kg and mB = 0.81 kg are connected by a string of negligible mass. They rest on a frictionless horizontal surface. You pull on block A with a horizontal force of 6.5 N. Determine the tension in the string connecting the two blocks.

Answer 1

Answer:

Explanation:

Given

Mass of block A $(m_a)$=2.6 kg

Mass of block B $(m_b)$=0.81 kg

Force of 6.5 N is applied on Block A

Force on Block A is F, Tension

thus

$F-T=m_a\times a$ -----1

where a=acceleration of the system

For Block B

$T=m_b\times a$ -----2

$F=m_b\times a+m_a\times a$

$F=\left ( m_a+m_b\right )a$

$F=\left ( 2.6+0.81\right )a$

$a=\frac{6.5}{3.41}$

$a=1.96 m/s^2$

$T=0.81\times 1.96=1.54 N$