The distance between slit and the screen is 1.214m.
To find the answer, we have to know about the width of the central maximum.
<h3>How to find the distance between slit and the screen?</h3>
- It is given that, wavelength 560 nm passes through a slit of width 0. 170 mm, and the width of the central maximum on a screen is 8. 00 mm.
- We have the expression for slit width w as,
                            
where, d is the distance between slit and the screen, and a is the slit width.
- Thus, distance between slit and the screen is,
                            
Thus, we can conclude that, the distance between slit and the screen is 1.214m.
Learn more about the width of the central maximum here:
brainly.com/question/13088191
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Change in state(from liquid to solid) and change in colour I believe.
        
             
        
        
        
The kinetic energy (KE) is 250 J and the gravitational potential energy (GPE) is 392 J
        
             
        
        
        
Electromagnetic waves need no matter to travel - they can travel through empty space (a vacuum). In a vacuum, all electromagnetic waves travel at approximately 3 x 108 m/s - which is the fastest speed possible. ... 
Light traveling value through an optical Fibre is, 2 x 108 m/s. Hope that helps.