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3 years ago

2 CuCl2 + 2 NaNO3 ---> Cu(NO3)2 + 2 NaCl

Chemistry

2 answers:

RUDIKE [14]3 years ago

4 0

This sums up solution for both the questions ;-)

Marina86 [1]3 years ago

4 0

The person above is right

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a student balanced the chemical equation for the reaction of magnesium with oxygen by writing Mg + O2 ----> MgO2. What is wro

egoroff_w [7]

Answer:

Explanation:

Magnesium when it oxidizes has a valence of 2.

Oxygen, when it mixes with something, has a valence of - 2

So Mg and O2 will form something, but what? The answer is MgO

Mg + O2 ===> MgO

To balance this equation, you need 2 Magnesiums on the right and 2 Oxygens also on the right. The left will need a two Magnesiums.

The balanced equation will be

2Mg + O2 ====> 2MgO

6 0

4 years ago

A compound can have different chemical and physical properties than

Marizza181 [45]

Answer: It's true

Explanation:

7 0

3 years ago

A student calculates the mass of a piece of copper to be 8.3 grams. The actual mass of the copper is 10. grams. What is the perc

jok3333 [9.3K]

Answer:

17%

Explanation:

Mass of a piece of copper calculated by student = 8.3 grams

Actual mass of copper = 10 grams

We know the formula for the percent error:

Percentage error = (| experimental value - actual value | / actual value) * 100

So substituting the given values in the above formula:

Percent error = (|8.3 - 10| / 10) * 100 = (1.7/10) * 100 = 17%

3 0

4 years ago

Production of Jam from Crushed Fruit in Two Stages. In a process producing jam (C1), crushed fruit containing 14 wt % soluble so

Andrej [43]

Answer:

The total kg from the mixer: $m=2222.5 kg$

Evaporated water: $m_{water ev.}=791.1 kg$

Jam produced: $m_{jam}=1431.4 kg$

Explanation:

Step by step:

1) Kg of mixture from the mixer

It says that crushed fruit is added to the mixer with the sugar and pectin.

The fruit added is 1000 kg

The sugar added is 1.22 kg sugar/1 kg crushed fruit:

$m_{sugar}=1000 kg fruit * \frac{1.22 kg sugar}{1 kg fruit}=1220 kg sugar$

The pectin added is 0.0025 kg pectin/1 kg crushed fruit:

$m_{pectin}=1000 kg fruit * \frac{0.0025 kg pectin}{1 kg fruit}=2.5 kg pectin$

The total kg from the mixer:

$m=1000 kg fruit + 2.5 kg pectin + 1220 kg sugar=2222.5 kg$

2) Evaporated water

To calculate the evaporated water it's important to have in mind that the mix goes from a concentration of 14 wt% to 67 wt%. This difference is because of the evaporated water. So:

Initial: 1000 kg of fruit with 14 wt% of solids

$m_{solids}=1000 kg *0.14=140 kg$

This amount of solids is constant

Final: The mass of solids is the same but now it represents the 67 wt%

$m_{final}=140 kg *\frac{100}{67}=208.9 kg$

and

$m_{water ev.}=1000kg-m_{final}$

$m_{water ev.}=1000kg-208.9kg=791.1 kg$

3) Jam produced

$m_{jam}=m_{final}+m_{pectin}+m_{sugar}=208.9 kg + 1220 kg + 2.5 kg$

$m_{jam}=1431.4 kg$

6 0

3 years ago

Can the same fertilizer be applied to all types of soil ? Explain

Arte-miy333 [17]

You cant use the same fertilizer for all soils bc differnt soils have different nutrients like lets say ur growing tomatoes with cabbage it wouldnt work bc they need different nutrients for them to grow. This is used with trees, veggies, plants and fruits. it is true somw can use the same fertilizer if they can be grown with it. if you give it the wrong nutrients it can die or not grow

4 0

3 years ago