Answer:
See explanation
Explanation:
We know that the process of the oxidation of SO2 to SO3 is catalysed by NO2 gas. It occurs in two stages and i will show the balanced reaction equation of the both stages below;
Step 1
2NO2(g) + 2SO2(g) ------> 2NO(g) + 2SO3(g)
Step 2
2NO(g) + O2(g) -------> 2NO2(g)
So, the overall reaction equation is;
2SO2(g) + O2(g) ------> 2SO3(g)
Polarity is the chemical property based on the electric charge and orientation of the poles. Al−O>H−Br>As−S is arranged in decreasing order of polarity. Thus, option d is correct.
<h3>What is polarity?</h3>
Polarity is a chemical property of the distribution of the electrical charges over their respective atom in the molecule joined by the bonds. The relation between the polarity and the difference in electronegativity is directly proportional.
The electronegativity difference between the elements are:
- Al−O = 1.8
- H−Br = 0.8
- As−S = 0.4
As the electronegativity difference between Al−O = 1.8 is the highest it will have the highest polarity followed by H−Br = 0.8, and As−S = 0.4, with the lowest polarity.
Therefore, option D. Al−O>H−Br>As−S is arranged in decreasing order of polarity.
Learn more about electronegativity here:
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Answer: Atoms that make up reactants rearrange into new products
Explanation:
A chemical reaction is the process of breaking down the chemical bonds of the reacting substances which are commonly called as reactants and making new bonds to form new substances commonly called as products.
The products will contain the same atoms as there are in the reactants but the bonds will rearrange to form different substances.
Every chemical reaction is accompanied with absorption or release of energy.
Answer:
NaNO3 (solubility = 89.0 g/100 g H2O)
Explanation:
The solubility of a specie is the amount of solute that will dissolve in one litre of the solvent. Solubility is usually expressed in units of molarity.
Now let us calculate the molarity of the NaNO3 (solubility = 89.0 g/100 g H2O)
Molar mass of NaNO3= 23+14+3(16)= 85gmol-1
Mass of solute=89.0g
Amount of solute= mass of NaNO3/molar mass of NaNO3
Amount of solute= 89.0g/85.0 gmol-1
= 1.0moles of NaNO3
Note that 100g of water=100cm^3 of water.
If 1.0 moles of NaNO3 dissolve in 100cm^3 or water therefore,
x moles of NaNO3 will dissolve in 1000cm^3 of water
x= 1.0 × 1000/ 100
x= 10.0 moles of NaNO3
