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ludmilkaskok [199]
3 years ago
9

Help 20 points !!!!!!!!!!!!!!!!!!!!!!!!!!!! plz do all no scammers

Chemistry
2 answers:
sattari [20]3 years ago
4 0
14 - 2nd one
15 - I do not know
16 - also do not know
Sorry
Katena32 [7]3 years ago
4 0

Answer:

oop

Explanation:

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What mass of boron sulfide must be processed with 2.1 x 10 4g of carbon to yield 3.11 x 10 4 g of boron and 1.47 x 10 5 g of car
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The reaction between boron sulfide and carbon is given as:

2B2S3 + 3C → 4B + 3CS2

As per the law of conservation of mass, for any chemical reaction the total mass of reactants must be equal to the total mass of the products.

Given data:

Mass of C = 2.1 * 10^ 4 g

Mass of B = 3.11*10^4 g

Mass of CS2 = 1.47*10^5

Mass of B2S3 = ?

Now based on the law of conservation of mass:

Mass of B2S3 + mass C = mass of B + mass of CS2

Mass of B2S3 + 2.1 * 10^ 4 = 3.11*10^4 + 1.47*10^5

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Chemical reactions are balanced by adding coefficients so that the number of atoms of each element is the same on both sides. Stoichiometry describes the relationship between the amounts of reactants and products in a reaction.

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