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miskamm [114]
3 years ago
13

A certain element exists as two different isotopes. 90.50% of its atoms have a mass of 20.00 amu and 9.500% of its atoms have a

mass of 22.00 amu. What is the average atomic mass of this element? (Do not round your answer)
Chemistry
1 answer:
Serga [27]3 years ago
6 0

Answer:

20.19 amu.

Explanation:

From the question given above, the following data were obtained:

Isotope A:

Abundance (A%) = 90.5%

Mass of A = 20 amu

Isotope B:

Abundance (B%) = 9.5%

Mass of B = 22 amu

Average atomic mass =..?

The average atomic mass of the element can be obtained as follow:

Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

Average atomic mass = [(20 × 90.5)/100] + [(22 × 9.5)/100]

Average atomic mass = 18.1 + 2.09

Average atomic mass = 20.19 amu

Therefore, the average atomic mass of the element is 20.19 amu

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9. Write the number in place value table of 820245<br>​
Burka [1]

Answer:

8----hundred thousands

2----ten thousands

0----thousands

2----hundreds

4----tens

5---ones

place value

 8 = 800,000

 2 = 20,000

 0 = 0,000

2 = 200

4 =40

5 =5

5 0
3 years ago
What property did mosely use to organize the periodic table?​
zhenek [66]

Answer:

nitrogen i think but not sure

Explanation:

4 0
3 years ago
You have a saturated solution of BaSO4, a slightly soluble ionic compound. What happens if you add Ba(OH)2, NaNO3, and CuSO4 to
igomit [66]

Answer:

- Addition of Ba(OH)2: favors the formation of a precipitate.

- Undergo a chemical reaction forming soluble species.

- Addition of CuSO4 : favors the formation of a precipitate.

Explanation:

Hello,

In this case, since the dissociation reaction of barium sulfate is:

BaSO_4(s)\rightleftharpoons Ba^{2+}(aq)+SO_4^{2-}(aq)

We must analyze the effect of the common ion:

- By adding barium hydroxide, more barium ions will be added to the equilibrium system so the formation of solid barium sulfate will be favored (reaction shifts leftwards towards reactants).

- By adding sodium nitrate, the following reaction will undergo:

BaSO_4(s)+NaNO_3(aq)\rightarrow Ba(NO_3)_2(aq)+Na_2SO_4(aq)

So the precipitate will turn into other soluble species.

- By adding copper (II) sulfate, more sulfate ions will be added to the equilibrium system so the formation of solid barium sulfate will be favored (reaction shifts leftwards towards reactants).

All of this is supported by the Le Chatelier's principle.

Best regards.

7 0
3 years ago
For each of the following compounds, state whether it is ionic or covalent, and if it is ionic, write the symbols for the ions i
kupik [55]

Answer :

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

All the polyatomic ions always form an ionic compound.

Polyatomic ions : It is a charged species that composed of two or more atoms and these charged species are bonded by the covalent bond.

For the given options:

Option A:  KClO_4

This compound is formed by the combination of potassium, K^+ which is a metal and ClO_4^- ion which is a polyatomic ion. Thus, it will form an ionic compound.

Option B:  Mg(C_2H_3O_2)_2

This compound is formed by the combination of magnesium, Mg^{2+} which is a metal and C_2H_3O_2^{-} ion which is a polyatomic ion. Thus, it will form an ionic compound.

Option C:  H_2S

Hydrogen and sulfur, both are non-metals and they will form a covalent compound.

Option D:  Ag_2S

This compound is formed by the combination of silver, Ag^{+} which is a metal and sulfur, S^{2-} which is a non-metal. Thus, it will form an ionic compound.

Option E:  N_2Cl_4

Nitrogen and chlorine, both are non-metals and they will form a covalent compound.

Option F:  Co(NO_3)_2

This compound is formed by the combination of cobalt, Co^{2+} which is a metal and NO_3^{-} ion which is a polyatomic ion. Thus, it will form an ionic compound.

6 0
3 years ago
A 3.42 gram sample of an unknown gas is found to occupy a volume of 1.90 L at a pressure of 547 mm Hg and a temperature of 33 °C
liq [111]
Use the Ideal Gas Law to find the moles of gas first.

Be sure to convert T from Celsius to Kelvin by adding 273.

Also I prefer to deal with pressure in atm rather than mmHg, so divide the pressure by 760 to get it in atm.

PV = nRT —> n = PV/RT
P = 547 mmHg = 547/760 atm = 0.720 atm
V = 1.90 L
T = 33°C = 33 + 273 K = 306 K
R = 0.08206 L atm / mol K

n = (0.720 atm)(1.90 L) / (0.08206 L atm / mol K)(306 K) = 0.0545 mol of gas

Now divide grams by mol to get the molecular weight.

3.42 g / 0.0545 mol = 62.8 g/mol
3 0
3 years ago
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